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Vertex of graph x2-6x plus 5?
y=aX2+bX+c ---> y=X2-6X+5vertex formula is -b/2a( b=-6,a=1)vertex=-(-6)/2*1=6/2=3 y=32-6(3)+5---->y=-4so vertex is (3,4)
What is the vertex of y equals x-3 plus 2?
The equation is linear and so has no vertex.
What is the vertex of y equals x2-6x plus 6?
(3, -21)
How do you graph y equals x2 plus 6x plus 7?
y = x2 + 6x + 7a = 1, b = 6, c = 7Since a is positive, the graph opens upward. You can find the vertex coordinates (-b/2a, f(-b/2a)) = (-3, f(-3)) = (-3, -2), so the equation of the axis of symmetry is x = -b/2a = -3, plot the y-intercept point (0, 7), plot the point (-b/a, 7) = (-6, 7), and draw the graph that passes through these points.Or complete the square.y = x2 + 6x + 7y = x2 + 6x + 9 - 9 + 7y = (x2 + 6x + 9) - 2y = (x + 3)2 - 2So start with the graph of y = x2 whose vertex is at the origin. Move it 3 units to the left, and 2 units do
How do you re-write x squared plus 5x - 3 in vertex form?
8
