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Q: What is x if negative ln x equals x?
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Solve e raised to the power of negative x equals 6?

e-x = 6Take the natural log of both sides:ln(e-x) = ln(6)-x = ln(6)x = -ln(6)So x = -ln(6), which is about -1.792.


How do you work out Ln 24 - ln x equals ln 6?

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What is the answer to 2 minus Ln times 3 minus x equal 0?

so, if 2 minus Ln times 3 minus x equals 0, then 2 minus Ln times 3 equals x, therefore 2 minus Ln equals x divided by three, so Ln + X/3 = 2 therefore, (Ln + [X/3]) = 1


What is the domain of y equals ln x?

In elementary mathematics, any subset of R+, the non-negative real numbers.


How do you solve for x 3 ln x - ln 3x equals 0?

3 ln(x) = ln(3x)ln(x3) = ln(3x)x3 = 3xx2 = 3x = sqrt(3)x = 1.732 (rounded)


What is the derivative of y equals xlnx?

Use the product rule.y = x lnxy' = x (ln x)' + x' (ln x) = x (1/x) + 1 ln x = 1 + ln xUse the product rule.y = x lnxy' = x (ln x)' + x' (ln x) = x (1/x) + 1 ln x = 1 + ln xUse the product rule.y = x lnxy' = x (ln x)' + x' (ln x) = x (1/x) + 1 ln x = 1 + ln xUse the product rule.y = x lnxy' = x (ln x)' + x' (ln x) = x (1/x) + 1 ln x = 1 + ln x


How do you solve ln 5 plus ln x equals 1?

5 + (-4) = 1 x = -4


How do you solve this logarithmic equation -3 plus ln x equals 5?

-3 + ln(x) = 5 ln(x) = 8 eln(x) = e8 x = e8 x =~ 2981


What is the average rate of change from x equals 2 to x equals 3 for the function f of x equals 3 ln x?

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Solve or x 2 ln 9 plus 2 ln 5 equals 2 ln x minus 3?

2 ln(9) + 2 ln(5) = 2 ln(x) - 3ln(81) + ln(25) = ln(x2) - 37.61332 = ln(x2) - 3ln(x2) = 10.61332ln(x) = 5.30666x = e5.30666 = 201.676 (rounded)


Is there a function where the first derivative goes to infinity for x going to 0 and where the first derivative equals 0 when x is 1?

Yes, the function ln(x) where ln is the logarithm to base e.Yes, the function ln(x) where ln is the logarithm to base e.Yes, the function ln(x) where ln is the logarithm to base e.Yes, the function ln(x) where ln is the logarithm to base e.


If e to the power x equals 0.4634 find x?

the natural log, ln, is the inverse of the exponential. so you can take the natural log of both sides of the equation and you get... ln(e^(x))=ln(.4634) ln(e^(x))=x because ln and e are inverses so we are left with x = ln(.4634) x = -0.769165