If you mean y2+8y+7=0 then it is a quadratic. y2+8y+7+9-9=0 y2+8y+16-9=0 (y+4)2=9 y+4=3 , y+4=-3 y=-1 , y=-7 So y can equal -1 or -7.
Let's first reformat it: x2 + y2 - 12x - 8y - 43 = 0 x2 - 12x + 36 + y2 - 8y + 16 = 43 + 36 + 16 (x - 6)2 + (y - 4)2 = 95 So this equation defines a circle, with a center point at (6, 4) and a perimeter (i.e. circumference) of √95.
x2 + 2y - 6x + 8y - 1 = x2 - y2 + 4x + 6y - 1 y2 - 10x + 4y = 0 y(y+4) = 10x It cannot be solved completely because with two variables (x and y) you need two independent equations for a full solution.
x2 + y2 + 6x + 8y - 24 = 0 add 32, 42, and 24 to both sides to complete the squares (x2 + 6x + 32) + (y2 + 8y + 42) = 9 + 16 + 24 (x + 3)2 + (y + 4)2 = 49 [x - (-3)]2 + [y - (-4)]2 = 72 Center: (-3, -4) Radius: 7
If: -8y-7 = -8+8y Then: -7+8 = 8y+8y And: 16y = 1 So: y = 1/16
If you mean y2+8y+7=0 then it is a quadratic. y2+8y+7+9-9=0 y2+8y+16-9=0 (y+4)2=9 y+4=3 , y+4=-3 y=-1 , y=-7 So y can equal -1 or -7.
88 + 5y - y2 66 - 3y + y2 Subtract: 22 + 8y -2y2
y2 + 8y + 16 = y2 + 4y + 4y + 16 = y(y + 4) + 4(y + 4) = (y + 4)(y + 4) or (y + 4)2
y2 +8y + 16 = 0 can factor to (y+4) (y+4) = 0 so y+4 = 0 so y = -4
I'm going to go out on a limb and assume that y2 8y c actually means y^2 + 8y + c c = 16 makes a perfect square: (y + 4)^2 = (y+4)*(y+4) = y^2 + 8y + 16
It goes to (x-5)(x-3)
Let's first reformat it: x2 + y2 - 12x - 8y - 43 = 0 x2 - 12x + 36 + y2 - 8y + 16 = 43 + 36 + 16 (x - 6)2 + (y - 4)2 = 95 So this equation defines a circle, with a center point at (6, 4) and a perimeter (i.e. circumference) of √95.
The standard equation of a circle with center C(h,k) and radius r is as follows:(x - h)2 + (y - k)2 = r2(x2 -2hx +h2) + (y2 - 2ky + k2)We have...x2 + y2 - 10x + 8y + 5 =0x2 - 10x + y2 + 8y + 5 =0add h2 and k2 to both sides(x2 - 10x + h2) + (y2 + 8y + k2) = -5 + h2 + k2Using the above framework we can see that 10 = 2h, h = 5Using the above framework we can see that 8 = 2k, k = 4So the formula is(x2 - 10x + 25) + (y2 + 8y + 16) = -5 + 25 + 16(x - 5)2 + (y - 4)2 = 36the center of the circle is C(5,4) and radius 6
x2 + 2y - 6x + 8y - 1 = x2 - y2 + 4x + 6y - 1 y2 - 10x + 4y = 0 y(y+4) = 10x It cannot be solved completely because with two variables (x and y) you need two independent equations for a full solution.
I assume you meant y2 = 8y + 8x? Subtract 8y: y2 - 8y = 8x. Complete the square: y2 - 8y + 16 = 8x + 16. Extract roots: (y - 4)2 = 8x + 16. Divide by 8: (1/8)(y - 4)2 = x + 2. So the vertex is (-2, 4). To find the focus, first consider the parabola y2/8 = x, which is nothing more than the same parabola, shifted down 4 and leftward 2. To find it's constant distance between focus and directrix, use the equation x = [1/(4p)]y2, and notice that 1/(4p) = 1/8. Solve this equation. Take the reciprocal: 4p = 8. Divide by 4: p = 2. So the distance is 2. It opens to the right, so the focus is 2 to the right of the vertex. The original parabola is the same thing, only translated, so the same thing applies - thus, the focus is 2 to the right of (-2, 4), or (0, 4).
x2 + y2 + 6x + 8y - 24 = 0 add 32, 42, and 24 to both sides to complete the squares (x2 + 6x + 32) + (y2 + 8y + 42) = 9 + 16 + 24 (x + 3)2 + (y + 4)2 = 49 [x - (-3)]2 + [y - (-4)]2 = 72 Center: (-3, -4) Radius: 7
If: -8y-7 = -8+8y Then: -7+8 = 8y+8y And: 16y = 1 So: y = 1/16