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What is the answer to y2 plus 8y plus 7?
If you mean y2+8y+7=0 then it is a quadratic. y2+8y+7+9-9=0 y2+8y+16-9=0 (y+4)2=9 y+4=3 , y+4=-3 y=-1 , y=-7 So y can equal -1 or -7.
What is the perimeter of the curve x2 plus y2-12x-8y-43 equals 0?
Let's first reformat it: x2 + y2 - 12x - 8y - 43 = 0 x2 - 12x + 36 + y2 - 8y + 16 = 43 + 36 + 16 (x - 6)2 + (y - 4)2 = 95 So this equation defines a circle, with a center point at (6, 4) and a perimeter (i.e. circumference) of √95.
What is the solution to x2 plus 2y-6x plus 8y-1 equals x2-y2 plus 4x-6y-1?
x2 + 2y - 6x + 8y - 1 = x2 - y2 + 4x + 6y - 1 y2 - 10x + 4y = 0 y(y+4) = 10x It cannot be solved completely because with two variables (x and y) you need two independent equations for a full solution.
What is the center and radius of the graph of the circle of x squared plus y squared plus 6x minus 8y minus 24 0?
x2 + y2 + 6x + 8y - 24 = 0 add 32, 42, and 24 to both sides to complete the squares (x2 + 6x + 32) + (y2 + 8y + 42) = 9 + 16 + 24 (x + 3)2 + (y + 4)2 = 49 [x - (-3)]2 + [y - (-4)]2 = 72 Center: (-3, -4) Radius: 7
What is -8y - 7 equals -8 plus 8y?
If: -8y-7 = -8+8y Then: -7+8 = 8y+8y And: 16y = 1 So: y = 1/16
