Q: What times 4 Y?

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The value of y in the equation 5y = 4 is y = 0.8.

-3 times 4 times y = -12y

The product of y times 4 is equal to y multiplied by 4. Similarly, the product of y times 6 is equal to y multiplied by 6.

1*1*1*1*1+1=4 divided by4

5(x^2 + y)

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8

If that's y times 4, the answer is 4y

-3 times 4 times y = -12y

The value of y in the equation 5y = 4 is y = 0.8.

6(4+y)

Algebraic expressions are useful for translating problems into the language of mathematics. An algebraic expression for the problem "6 times the sum of 4 and y" would be: 6(4+y) = 24 + 6y.

The product of y times 4 is equal to y multiplied by 4. Similarly, the product of y times 6 is equal to y multiplied by 6.

If you meant (45x^4)(y), then the answer is: (3)(3)(5)(x)(x)(x)(x)(y) If you meant 45 times x times 4 times y, then the answer is: (2)(2)(3)(3)(5)(x)(y)

y4 times y3 = y7

1*1*1*1*1+1=4 divided by4

x^(4)*y*x^(5)*yMultiply x^(4) by y to get x^(4)y.(d)/(dx) x^(4)*y*x^(5)*y=x^(4)y*x^(5)*yMultiply x^(4)y by x^(5) to get x^(9)y.(d)/(dx) x^(4)*y*x^(5)*y=x^(9)y*yMultiply x^(9)y by y to get x^(9)y^(2).(d)/(dx) x^(4)*y*x^(5)*y=x^(9)y^(2)To find the derivative of x^(9)y^(2), multiply the base (x) by the exponent (9), then subtract 1 from the exponent.(d)/(dx) x^(4)*y*x^(5)*y=9x^(8)y^(2)The derivative of x^(4)*y*x^(5)*y is 9x^(8)y^(2).9x^(8)y^(2)

5(x^2 + y)