Well, let's think about this together. When we multiply a number by 4, we are essentially adding that number to itself 4 times. So, if we have Y and we multiply it by 4, we are finding the result of adding Y to itself 4 times. It's like creating a beautiful pattern of Y's that brings joy to our mathematical canvas.
The expression ( y^3 \times y ) can be simplified using the laws of exponents. When multiplying powers with the same base, you add the exponents: ( y^3 \times y^1 = y^{3+1} = y^4 ). Therefore, ( y^3 \times y = y^4 ).
-3 times 4 times y = -12y
If 5y = 4 then y = 4/5 or 0.8
When multiplying powers, you add them! y4 times y6 = y10. Try it with y = 2: 2 to the fourth = 16, 2 to the sixth = 64 16 x 64 = 1024 = 2 to the tenth.
1*1*1*1*1+1=4 divided by4
8
The expression ( y^3 \times y ) can be simplified using the laws of exponents. When multiplying powers with the same base, you add the exponents: ( y^3 \times y^1 = y^{3+1} = y^4 ). Therefore, ( y^3 \times y = y^4 ).
If that's y times 4, the answer is 4y
To find 4 times the sum of y and 7, you first calculate the sum of y and 7, which is y + 7. Then, you multiply this sum by 4 to get the final result. Therefore, the expression for 4 times the sum of y and 7 is 4(y + 7), which simplifies to 4y + 28.
-3 times 4 times y = -12y
If 5y = 4 then y = 4/5 or 0.8
6(4+y)
Algebraic expressions are useful for translating problems into the language of mathematics. An algebraic expression for the problem "6 times the sum of 4 and y" would be: 6(4+y) = 24 + 6y.
If you meant (45x^4)(y), then the answer is: (3)(3)(5)(x)(x)(x)(x)(y) If you meant 45 times x times 4 times y, then the answer is: (2)(2)(3)(3)(5)(x)(y)
When multiplying powers, you add them! y4 times y6 = y10. Try it with y = 2: 2 to the fourth = 16, 2 to the sixth = 64 16 x 64 = 1024 = 2 to the tenth.
y4 times y3 = y7
1*1*1*1*1+1=4 divided by4