6
To find the partial products of 28 and 43, you can break down the multiplication into simpler parts. First, multiply 28 by 3 (the tens place of 43), which gives you 84 (28 × 3). Then, multiply 28 by 40 (the tens place of 43 multiplied by 10), resulting in 1120 (28 × 40). The partial products are 84 and 1120.
30 x 20 = 600 30 x 8 = 240 4 x 20 = 80 4 x 8 = 32
They are: 30*20, 30*8, 2*20 and 2*8.
To find the partial product of 4 x 27, you can break down 27 into its components. For example, 27 can be expressed as 20 + 7. Then, you calculate the partial products: 4 x 20 = 80 and 4 x 7 = 28. Adding these together gives you a total of 80 + 28 = 108, so the partial products lead to the final result of 4 x 27 = 108.
They are 600, 240, 80 and 32.
34 x 28 = 34 x (20 + 8) First partial product is: (30 + 4) x 8 = 240 + 32 Second partial product is: (30 + 4) x 20 = 600 + 80 Sum of partial products = total product = 600 + 240 + 80 + 32 = 952
6
To find the partial products of 28 and 43, you can break down the multiplication into simpler parts. First, multiply 28 by 3 (the tens place of 43), which gives you 84 (28 × 3). Then, multiply 28 by 40 (the tens place of 43 multiplied by 10), resulting in 1120 (28 × 40). The partial products are 84 and 1120.
30 x 20 = 600 30 x 8 = 240 4 x 20 = 80 4 x 8 = 32
They are: 30*20, 30*8, 2*20 and 2*8.
how to find the partial products of a number
To find the partial product of 4 x 27, you can break down 27 into its components. For example, 27 can be expressed as 20 + 7. Then, you calculate the partial products: 4 x 20 = 80 and 4 x 7 = 28. Adding these together gives you a total of 80 + 28 = 108, so the partial products lead to the final result of 4 x 27 = 108.
4 x 20 = 80 4 x 7 = 28 80 + 28 = 108 4 x 27 = 108
5630 is a single number and single numbers do not have partial products.
the partial products for 12 and 3 30 and 6 :)
To find the partial products of 28 times 14, you would multiply each digit in the ones place of the second number (4) by each digit in the ones place of the first number (8), resulting in 32. Next, you would multiply each digit in the tens place of the second number (1) by each digit in the ones place of the first number (8), resulting in 8. Finally, you would add these two products together to get the final answer of 392.