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Which point lies outside the circle with equation (x - 2)2 (y 3)2 4?
2,0
The number of normals to the parabola from a point which lies outside?
We can draw 3 normals to a parabola from a given point as the equation of normal in parametric form is a cubic equation.
Is it true or false the solution set of an equation of a circle is all of the points that lie on the circle?
True. The solution set of an equation of a circle consists of all the points that lie on the circle itself. This set is defined by the equation ((x - h)^2 + (y - k)^2 = r^2), where ((h, k)) is the center and (r) is the radius. Thus, any point that satisfies this equation lies on the circle.
How do you determine if a point lies on the same line?
A point lies on a line if the coordinates of the point satisfy the equation of the line.
The solution set of an equation of a circle is all of the points that lie on the circle.?
Yes, the solution set of an equation of a circle consists of all the points that satisfy the equation, representing the circle's boundary. Typically, this equation is in the form ((x - h)^2 + (y - k)^2 = r^2), where ((h, k)) is the center and (r) is the radius. Each point ((x, y)) that meets this condition lies exactly on the circle.
Which point lies outside the circle with equation (x - 2)2 (y 3)2 4?
2,0
Is each point that lies on a circle satisfies the equation of the circle true or false?
True
The number of normals to the parabola from a point which lies outside?
We can draw 3 normals to a parabola from a given point as the equation of normal in parametric form is a cubic equation.
Is it true or false the solution set of an equation of a circle is all of the points that lie on the circle?
True. The solution set of an equation of a circle consists of all the points that lie on the circle itself. This set is defined by the equation ((x - h)^2 + (y - k)^2 = r^2), where ((h, k)) is the center and (r) is the radius. Thus, any point that satisfies this equation lies on the circle.
How do you determine if a point lies on the same line?
A point lies on a line if the coordinates of the point satisfy the equation of the line.
The solution set of an equation of a circle is all of the points that lie on the circle.?
Yes, the solution set of an equation of a circle consists of all the points that satisfy the equation, representing the circle's boundary. Typically, this equation is in the form ((x - h)^2 + (y - k)^2 = r^2), where ((h, k)) is the center and (r) is the radius. Each point ((x, y)) that meets this condition lies exactly on the circle.
If a circle is inscribed in a hexagon which of the following must be true?
A. The hexagon is circumscribed about the circle . D. Each vertex of the hexagon lies outside the circle . E. The circle is tangent to each side of the hexagon .
The solution set of an equation of a circle is all of the points that lie on a cirlce?
Yes, the solution set of an equation of a circle consists of all the points that satisfy the equation, which typically takes the form ((x - h)^2 + (y - k)^2 = r^2). Here, ((h, k)) represents the center of the circle, and (r) is its radius. Any point ((x, y)) that lies on the circle will fulfill this equation, thus forming the complete solution set.
How do you verify if a point lies on a circle?
If ... the square of (the x-coordinate of the point minus the x-coordinate of the center of the circle) added to the square of (the y-coordinate of the point minus the y-coordinate of the center of the circle) is equal to the square of the circle's radius, then the point is on the circle.
Which point lies on the line whose equation is 2x-3y9?
Without an equality sign it can not be considered to be an equation
How to draw great circles and small circles drawn?
To draw a great circle on a sphere, start by defining the diameter as the largest circle that can be drawn on the sphere's surface. For small circles, choose a point on the sphere and draw a circle with that point as the center and the radius less than the sphere's radius. Remember that the center of a small circle lies outside the circle on a sphere's surface.
What point lies on the equation y-3(x 5)?
The given expression is not an equation because it has no equality sign
