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Q: Which point lies outside the circle with equation x - 22 y 32 4?
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Given the coordinates xy of a center of a circle and its radius write a program which will determine whether a point lies inside the circleon the circle or outside the circle conditional statements?

Center is at (Xc, Yc ). Radius = R. ======================================= Print "Input the coordinates of point 'P', separated by a comma." Input A, B D = (Xc - A)2 + (Yc - B)2 If D < R2 then print "'P' is inside the circle." If D = R2 then print "'P' is on the circle." If D > R2 then print "'P' is outside the circle." by arup nandy


Given the coordinates xy of a center of a circle and it's radiuswrite a program which will determine whether a point lies inside the circleon the circle or outside the circle conditional statements?

Center is at (Xc, Yc ). Radius = R. ======================================= Print "Input the coordinates of point 'P', separated by a comma." Input A, B D = (Xc - A)2 + (Yc - B)2 If D < R2 then print "'P' is inside the circle." If D = R2 then print "'P' is on the circle." If D > R2 then print "'P' is outside the circle."


C program to find whether the given point lies inside or outside or in circle?

I'm not going to write the program for you, but the way to determine whether a point lies within a circle is very easy: just compare the distance between the point and the centerpoint of the circle with its radius. If the distance is smaller, it's inside the circle, if it's greater, then the point is outside.You can calculate the distance between the point and the centerpoint using Pythagoras's method. If the point is at (PX, PY) and the centerpoint is at (CX, CY), the distance can be calculated as such:DX = (CX - PX); // X distanceDY = (CY - PY); // Y distancedistance = sqrt( (DX * DX) + (DY * DY) );