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2,0
We can draw 3 normals to a parabola from a given point as the equation of normal in parametric form is a cubic equation.
A point lies on a line if the coordinates of the point satisfy the equation of the line.
If ... the square of (the x-coordinate of the point minus the x-coordinate of the center of the circle) added to the square of (the y-coordinate of the point minus the y-coordinate of the center of the circle) is equal to the square of the circle's radius, then the point is on the circle.
Without an equality sign it can not be considered to be an equation
2,0
True
We can draw 3 normals to a parabola from a given point as the equation of normal in parametric form is a cubic equation.
A point lies on a line if the coordinates of the point satisfy the equation of the line.
A. The hexagon is circumscribed about the circle . D. Each vertex of the hexagon lies outside the circle . E. The circle is tangent to each side of the hexagon .
If ... the square of (the x-coordinate of the point minus the x-coordinate of the center of the circle) added to the square of (the y-coordinate of the point minus the y-coordinate of the center of the circle) is equal to the square of the circle's radius, then the point is on the circle.
Without an equality sign it can not be considered to be an equation
The given expression is not an equation because it has no equality sign
(6,2)
Center is at (Xc, Yc ). Radius = R. ======================================= Print "Input the coordinates of point 'P', separated by a comma." Input A, B D = (Xc - A)2 + (Yc - B)2 If D < R2 then print "'P' is inside the circle." If D = R2 then print "'P' is on the circle." If D > R2 then print "'P' is outside the circle." by arup nandy
Center is at (Xc, Yc ). Radius = R. ======================================= Print "Input the coordinates of point 'P', separated by a comma." Input A, B D = (Xc - A)2 + (Yc - B)2 If D < R2 then print "'P' is inside the circle." If D = R2 then print "'P' is on the circle." If D > R2 then print "'P' is outside the circle."
I'm not going to write the program for you, but the way to determine whether a point lies within a circle is very easy: just compare the distance between the point and the centerpoint of the circle with its radius. If the distance is smaller, it's inside the circle, if it's greater, then the point is outside.You can calculate the distance between the point and the centerpoint using Pythagoras's method. If the point is at (PX, PY) and the centerpoint is at (CX, CY), the distance can be calculated as such:DX = (CX - PX); // X distanceDY = (CY - PY); // Y distancedistance = sqrt( (DX * DX) + (DY * DY) );