If you mean: -8x+y = 2 then y = 8x+2 and the line parallel to it will have the same slope of 8 but with a different y intercept.
Points: (3, 2) and (5, -1) Midpoint: (4, 0.5) End points of line: (0, 0) and (4, 0.5) Slope of line: 1/8 Equation of line: y-0.5 = 1/8(x-4) => y = 1/8x
Points: (3, -1) and (4, 7) Slope: 8 Equation: y = 8x-25
8 lol :]
The line 8x-8=0 is the same as x=1. The graph looks like a vertical line that intersects the x axis at x=1.
Points: (12, 8) and (17, 16) Slope: 8/5 Equation: 5y = 8x-32
If you mean: -8x+y = 2 then y = 8x+2 and the line parallel to it will have the same slope of 8 but with a different y intercept.
Points: (3, 2) and (5, -1) Midpoint: (4, 0.5) End points of line: (0, 0) and (4, 0.5) Slope of line: 1/8 Equation of line: y-0.5 = 1/8(x-4) => y = 1/8x
8x + 3y = 248x - 8x + 3y = -8x + 243y = - 8x + 243y/3 = (- 8x + 24)/3y = -8x/3 + 24/3y = (-8/3)x + 8 this is the slope-intercept form of the equation of the line, y = mx + b, where the slope m is -8/3 and the y-intercept b is 8.
Points: (3, -1) and (4, 7) Slope: 8 Equation: y = 8x-25
If that is 8x + 14 then the slope is 8. Or, written as a slope 8/1
It is 8 and the y intercept is 8
8 lol :]
-8x+3y=12 3y = 8x+12 y = (8/3)x + 4 So it will be a line with slope 8/3 and y intercept of 4
The line 8x-8=0 is the same as x=1. The graph looks like a vertical line that intersects the x axis at x=1.
If you mean: 8x-2y = 16 then the points are (2, 0) and (0, -8) which means x intercept is 2 and y intercept is -8
Points: (-4, 1) and (4, -6) Slope: -7/8 Equation: y = -7/8x-5/2 or as 7x+8y+20 = 0