Presumably this is a simultaneous equation in the form of:
x = 8-2y
y-x = 4
Which is the same as:
2y+x = 8
y-x = 4
Add both equations together:
3y = 12.
So y will equal 4.
Substitute the value of y into the original equations to find the value of x:
So: x = 0 and y = 4
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x + y = -4x - y = 2x - y = 2x + y - y = 2 + yx = 2 + yx + y = -42 + y + y = -42 + 2y = -42 - 2 + 2y = -4 - 22y = -62y/2 = -6/2y = -3x = 2 + yx = 2 - 3x = -1The solution of the system is (-1, -3)
y = 0x = y + 2plug 0 in for yx = 0 + 2x = 2
If you mean y = x+5 and x is -1 then y = 4
If you mean: y = x+4 then the perpendicular equation can be y = -0.5x+4
If the x=4, then its equivelent to 12 + 4, which equals 16.