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Presumably this is a simultaneous equation in the form of:

x = 8-2y

y-x = 4

Which is the same as:

2y+x = 8

y-x = 4

Add both equations together:

3y = 12.

So y will equal 4.

Substitute the value of y into the original equations to find the value of x:

So: x = 0 and y = 4

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Q: X equals 8-2y y-x equals 4?
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