That doesn't factor neatly. Applying the quadratic formula, we find two imaginary solutions: -3 plus or minus i, where i is the square root of negative 1.
(3x + 5)(x2 - 2)
x2 + 6x - 72 = (x + 12)(x - 6)
x2+6x-7 = (x+7)(x-1) when factored
To factorise this completely you need to be aware that 216 = 63. (x3 + 216) = (x + 6)(x2 - 6x + 36)
x2 - x + 30 does not have any factors. If on the other hand you wanted to factor out: x2 - x - 30 Then it can be done as follows: = x2 - 6x + 5x - 30 = x(x - 6) + 5(x - 6) = (x + 5)(x - 6)
x2 + 6x - 27 = (x + 9)(x - 3)
x2-6x can be factored into x(x-6). Simply factor out the "x" from both factors.
You didn't bother to list the binomials to choose from, but the two binomial factors of x2 + 6x - 40 are (x + 10) and (x - 4)
(3x + 5)(x2 - 2)
x2+6x-40 = 0 (x+10)(x-4) = 0 x = 4 or x = -10
(X + 5)(X + 1) FOIL this. X2 + 1X + 5X + 5 Gather terms. X2 + 6X + 5 ----------------------------those were the factors
X2 - 6X + 27 = 0 what are the factors of 27 that add to - 6? None! This polynomial is unreal and does not intersect the X axis.
x2 + 6x - 2 can not be factored
(x - 4)(x - 2)
please help on this x2+6x+27=
x2 + 6x = x*(x + 6)
Um.......is it x2+6x or x2-6x. I think your missing some things here champ