x2 + 100 has no real solutions. Applying the quadratic formula, we find two imaginary solutions: Zero plus or minus 10itimes the square root of 1.
x = 10i
x = -10i
where i is the square root of negative 1.
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That doesn't factor neatly. Applying the quadratic formula, we find two imaginary solutions: (-1 plus or minus the square root of -31) divided by 2.
x = -0.5 + 2.7838821814150108i
x = -0.5 - 2.7838821814150108i
where i is the square root of negative one.
6(ab - ac + b2 - bc)
6ab(2x2+x-5)
(x - 5)(x - 3)
Remember to factor out the GCF of the coefficients if there is one. A perfect square binomial will always follow the pattern a squared plus or minus 2ab plus b squared. If it's plus 2ab, that factors to (a + b)(a + b) If it's minus 2ab, that factors to (a - b)(a - b)
(6x - 1)(6x - 1)