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How do you factor x squared - 9x?
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How do you factor 9x squared-18?
I hope you mean x3+2x2-9x+18. Treat the equation like two equations: x3+2x2 and 9x+18. Factor out x2 from the first equation, so x2(x+2). Factor out 9 from the second equation, so 9(x+2). Now, the whole equation. x2(x+2)-9(x+2). Factor out (x+2), so (x+2)(x2-9). (x2-9) factors into (x+3)(x-3). So, (x+2)(x+3)(x-3) is the complete factorization. Hope this helps.
How do you factor 3x2-9x-912?
3x2 - 9x - 912 = 3(x2 - 3x - 304) = 3(x - 19)(x + 16).
Factor this 9x2 plus 27?
9x(x2+3x-10) * * * * * 9x3 + 27x2 - 90x = 9x(x2 + 3x - 10) = 9x(x + 5)(x - 2).
How do you factor x2-x-20?
(x - 5)(x + 4)
What is x2 equals 9x-20?
x2=9x-20 x2-9x+20=0 Factor: (x-4)(x-5)=0 x={4,5}
How do you factor x2-9x?
x2-9x = x(x-9)
Factor x2 plus 9 plus 20?
x2 + 9 + 20 = x2 + 29, and can not be factored.I assume though that you mis-wrote your question, and what you in fact want to ask is how to factor x2 + 9x + 20.In that case, the answer is (x + 4)(x + 5).
How do you factor x2 - 9x equals -8?
x2 - 9x = -8 ∴ x2 - 9x + 8 = 0 ∴ (x - 1)(x - 8) = 0 You can then solve it as well: ∴ x ∈ {1, 8}
Factor 9x cubed plus 27x squared -90x?
Step 1: Divide by 9x: 9x (x2 + 3x - 10) = 9x(x + 5)(x - 2)
What binomial is a factor of both x2 plus 5x-36 and x2-9x plus 20?
x - 4. x^2 + 5x - 36 = (x - 4) (x + 9) x^2 - 9x + 20 = (x - 4) (x - 5)
What is the polynomial of this factor x2 minus 9x plus 18 in descending order?
x2 - 9x + 18 = (x - 3)(x - 6)
What are the solutions to x2 plus 20 -9x?
Not being an equation, it does not have a "solution" per se. If you wish to factor it, you can do it like so: x2 + 20 - 9x = x2 - 5x - 4x + 20 = x(x - 5) - 4(x - 5) = (x - 4)(x - 5) If that expression is equal to zero, then x would be equal to 4 or 5.
How do you factor x3-729?
(x - 9)(x2 + 9x + 81)
How do you factor x2 9x-144?
You don't. This expression does not have any factors.
How do you factor x2-9x-10?
(x - 10)(x + 1)
Factor x2-9x plus 18?
x^2-9x+18=(x-6)(x-3)
