Divide all terms by -1 so that:-
10b2+27b+18 = 0
(5b+6)(2b+3) = 0
So: b = -6/5 or b = -3/2
That factors to 2(x + 4)(x + 6) x = -4, -6
I'm presuming its factors for a monic quadratic trinomial--of form : X squared + BX + C . You need the numbers that MULTIPLY to give C and ADD up to give B Eg X squared + 8X + 12 factors to ( X+2) (X + 6 ) BUT X squared + 7X + 12 factors to (X +3 )(X + 4) Hope this helps. Phil.
This is a hyperbola. It is best approached using Fermat's factorisation method. Seefermat-s-factorization-methodor google wikepedia. I don't know of any faster approach.
Whenever there are polynomials of the form aX2+bX+c=0 then this type of equation is know as a quadratic equation. to solve these we usually break b into two parts such that there product is equal to a*c and I hope you know how to factor polynomials.
5x squared plus 33x plus 18 = (5x + 3)(x + 6) x = -6, -3/5
Solve using the quadratic formula
The quadratic formula is used to solve the quadratic equation. Many equations in which the variable is squared can be written as a quadratic equation, and then solved with the quadratic formula.
It can be solved by using the quadratic equation formula.
-34
You can't because it is not a quadratic equation.
Using the quadratic equation formula: x = 8.42 or x = -1.42
I suggest you use the quadratic formula, with a = 3, b = -2, c = 7.
You don't need to use the quadratic formula because:- 5r2 = 80 Divide both sides by 5: x2 = 16 Square root both sides: r = 4
It can't be solved because the discriminant of the given quadratic equation is less than zero meaning it has no real roots.
x2+x-15 = 0 Using the quadratic equation formula: x = 3.405124838 or x = -4.405124838
Use the quadratic formula, with a = 1, b = -10, c = 29.Use the quadratic formula, with a = 1, b = -10, c = 29.Use the quadratic formula, with a = 1, b = -10, c = 29.Use the quadratic formula, with a = 1, b = -10, c = 29.
Use the quadratic formula. x = -4.265564 or -0.234436