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What is the prime factorization using divisibility rules for 1215?
1215 is divisible by 3 because its digits add up to a multiple of 3. That leaves 405. 405 is divisible by 3, leaving 135. 135 is divisible by 3, leaving 45. 45 is divisible by 3, leaving 15. 15 is divisible by 3, leaving 5. 5 is divisible by 5 because it ends in 5. 3 x 3 x 3 x 3 x 3 x 5 = 1215
Which number is divisible by 3 and 5 601848 or 12?
Both are divisible by 3 and 5 12/3 = 4 12/5 = 2.4 601848/3 = 200616 601848/5 = 40123.2 However both are only divisible by 3 with no remainder.
Is 3 divisible by 870?
No. But 870 is divisible by 3 (because 8+7+0 = 15 -> 1 + 5 = 6 and 6 is divisible by 3). 870/3 = 290.
Is there a number divisible by 6. But not 3?
yeah3 9 15 21 27 and so on(every other multiple of three)But if you have a large number, like 755253, and don't have a calculator handy, then use sum of digits to determine if divisible by 3.Then if the number is divisible by 3 and divisible by 2, then it is also divisible by 6.So in this case: 7 + 5 + 5 + 2 + 5 + 3 = 27, which is divisible by 3, but the original number is odd, so the number is not divisible by 6.
What is 7055 divisible by?
2,055 is divisible by 1, 3, 5, 15, 137, 411, 685, 2055.
