x2 + 8x - 9 factors to (x - 1)(x + 9) x2 - 1 factors to (x - 1)(x + 1) The LCM will be (x - 1)(x + 1)(x + 9) or x3 + 9x2 - x - 9 The GCF is (x - 1)
x2 - y2 = 16 then (x + y)*(x - y) = 16 This has an infinite number of solutions lying on the hyperbola.
If: x2 = 81 Then: x = 9 or x = -9
x2 + 18x - 50 does not have rational factors.
If that's -16x, that factors to (x - 8)(x - 8) or (x - 8)2
-14
4(x2 - 2x + 4)
(x + 8)(x + 2)
x2 + 8x - 9 factors to (x - 1)(x + 9) x2 - 1 factors to (x - 1)(x + 1) The LCM will be (x - 1)(x + 1)(x + 9) or x3 + 9x2 - x - 9 The GCF is (x - 1)
(x+4)(x-4) (x + 4)(x - 4)
-((x + 2)(x - 8))
4(x2 - 4) 4(x + 2)(x - 2)
X2 - 16(X - 4)(X + 4)============X2 + 16===========not factorable in real numbers
Assuming that is x squared minus 16: x2 - 16 = (x + 4)(x - 4) (The difference of two squares.)
The factors of x2 are x and x.
That factors to 5(x - 4)(x + 4)(x2 + 16)
Given: x2 + 10x - 16 Let: x2 + 10x - 16 = 0 x2 + 10x - 16 = 0 ∴ x2 + 10x + 25 = 16 + 25 ∴ (x + 5)2 = 41 ∴ x = -5 ± √41 ∴ x2 + 10x - 16 = (x + 5 + √41)(x + 5 - √41)