(2 x 3) + (2 x 2) - 12 = -2
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2x3 + 8x2 + 3x + 12 = (2x3 + 8x2) + (3x + 12) = 2x2(x + 4) + 3(x + 4) = (x + 4)(2x2 + 3) Since you have asked this question I am assuming that you are not yet at a level where you might want (2x2 + 3) factorised into its imaginary factors.
(x + 1) / (2x3 + 3x + 5) --- Can't depict long division here, but you can work this out by seeing if (x + 1) is a factor of (2x3 + 3x + 5). If it is, then the answer will be 1/(the other factor). In this case, that is true. (2x3 + 3x + 5)/(x + 1) = 2x2 - 2x + 5, so the term term above is equal to: 1 / (2x2 - 2x + 5)
2x1 is 2 2x2 is 4 2x3 is 6 2x4 is 8 2x5 is 10 2x6 is 12
Well, 4 is 2X2 and 6 is 2X3 so the number needs two 2s and one 3 :2x2x3=12
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