A 9 x 12 rectangle has a diagonal of 15.
To find the length of the diagonal of a rectangle, we can use the Pythagorean theorem, which states that the square of the length of the diagonal is equal to the sum of the squares of the lengths of the two sides. In this case, the diagonal length (d) can be calculated as follows: d^2 = 30^2 + 50^2. Therefore, d^2 = 900 + 2500 = 3400. Taking the square root of 3400 gives us the diagonal length, which is approximately 58.3 feet.
Any you want as long as its AREA is 6991 sq ft. Some shapes and sizes which all have an area of 6991 sq ft are: A rectangle 1 ft x 6991 ft A rectangle 2 ft x 3495 ft 6 in A rectangle 3 ft x 2330 ft 4 in A rectangle 6 ft x 1165 ft 2 in A rectangle 12 ft x 582 ft 7 in A rectangle 40 ft x 174 ft 9.3 in A rectangle 60 ft x 116 ft 6.2 in A rectangle 66 ft x 105 ft 11 1/11 in A square approx 83.612 ft on each side A regular hexagon approx 63.532 ft on each side A circle of radius approx 47.173 ft
116
"X" = .66
43.26661530556787
The diagonal is 15.652'
Diagonal = square root of (24 squared + 26 squared) and that is square root of (576 + 676) and that is square root of (1252) and that is 35.38 feet
(Diagonal)2 = (36)2 + (26)2 = 1,972Diagonal = sqrt(1,972) = 44.4072 (rounded)
-- A rectangle has no 'formula'. -- The length of the diagonal is 24feet 10.62inches (rounded)
A 9 x 12 rectangle has a diagonal of 15.
104.1 feet
Yes, the diagonal of a rectangle is X.
Other side = 60 tan 20, so area of rectangle = 3600 tan 20 = 3600 x 0.36397= 1310.29 sq ft
To find the length of the diagonal of a rectangle, we can use the Pythagorean theorem, which states that the square of the length of the diagonal is equal to the sum of the squares of the lengths of the two sides. In this case, the diagonal length (d) can be calculated as follows: d^2 = 30^2 + 50^2. Therefore, d^2 = 900 + 2500 = 3400. Taking the square root of 3400 gives us the diagonal length, which is approximately 58.3 feet.
The diagonal is 69.856 feet.
Area of a rectangle = L x WA = 7 x 5A = 35 ft²