The length of the diagonal of an ( a , \text{ft} \times a , \text{ft} ) rectangle can be calculated using the Pythagorean theorem. The diagonal ( d ) is given by the formula ( d = \sqrt{a^2 + a^2} = \sqrt{2a^2} = a\sqrt{2} ). Therefore, the length of the diagonal is ( a\sqrt{2} ) feet.
To find the diagonal of a rectangle, you can use the Pythagorean theorem. For a rectangle with dimensions 30 ft and 48 ft, the diagonal (d) can be calculated using the formula (d = \sqrt{(30^2 + 48^2)}). This gives (d = \sqrt{(900 + 2304)} = \sqrt{3204} \approx 56.6) ft. Therefore, the diagonal is approximately 56.6 feet long.
To find the length of the diagonal of a rectangle, you can use the Pythagorean theorem. For a rectangle with length ( l = 36 ) ft and width ( w = 18 ) ft, the diagonal ( d ) can be calculated using the formula ( d = \sqrt{l^2 + w^2} ). Plugging in the values, ( d = \sqrt{36^2 + 18^2} = \sqrt{1296 + 324} = \sqrt{1620} ). This simplifies to ( d \approx 40.31 ) ft.
A 9 x 12 rectangle has a diagonal of 15.
To find the length of the diagonal of a rectangle, we can use the Pythagorean theorem, which states that the square of the length of the diagonal is equal to the sum of the squares of the lengths of the two sides. In this case, the diagonal length (d) can be calculated as follows: d^2 = 30^2 + 50^2. Therefore, d^2 = 900 + 2500 = 3400. Taking the square root of 3400 gives us the diagonal length, which is approximately 58.3 feet.
To find the diagonal measurement of a rectangle, you can use the Pythagorean theorem. For a rectangle measuring 16 feet by 38 feet, the diagonal (d) can be calculated as (d = \sqrt{(16^2 + 38^2)}). This results in (d = \sqrt{(256 + 1444)} = \sqrt{1700} \approx 41.23) feet. Therefore, the diagonal measurement is approximately 41.23 feet.
43.26661530556787
The diagonal is 15.652'
To find the diagonal of a rectangle, you can use the Pythagorean theorem. For a rectangle with dimensions 30 ft and 48 ft, the diagonal (d) can be calculated using the formula (d = \sqrt{(30^2 + 48^2)}). This gives (d = \sqrt{(900 + 2304)} = \sqrt{3204} \approx 56.6) ft. Therefore, the diagonal is approximately 56.6 feet long.
Diagonal = square root of (24 squared + 26 squared) and that is square root of (576 + 676) and that is square root of (1252) and that is 35.38 feet
(Diagonal)2 = (36)2 + (26)2 = 1,972Diagonal = sqrt(1,972) = 44.4072 (rounded)
To find the length of the diagonal of a rectangle, you can use the Pythagorean theorem. For a rectangle with length ( l = 36 ) ft and width ( w = 18 ) ft, the diagonal ( d ) can be calculated using the formula ( d = \sqrt{l^2 + w^2} ). Plugging in the values, ( d = \sqrt{36^2 + 18^2} = \sqrt{1296 + 324} = \sqrt{1620} ). This simplifies to ( d \approx 40.31 ) ft.
-- A rectangle has no 'formula'. -- The length of the diagonal is 24feet 10.62inches (rounded)
A 9 x 12 rectangle has a diagonal of 15.
104.1 feet
Yes, the diagonal of a rectangle is X.
Other side = 60 tan 20, so area of rectangle = 3600 tan 20 = 3600 x 0.36397= 1310.29 sq ft
To find the length of the diagonal of a rectangle, we can use the Pythagorean theorem, which states that the square of the length of the diagonal is equal to the sum of the squares of the lengths of the two sides. In this case, the diagonal length (d) can be calculated as follows: d^2 = 30^2 + 50^2. Therefore, d^2 = 900 + 2500 = 3400. Taking the square root of 3400 gives us the diagonal length, which is approximately 58.3 feet.