Oh, dude, you're hitting me with the math questions now? Okay, okay, so if you wanna find the diagonal of an 8 ft by 12 ft rectangle, you can use the Pythagorean theorem. It's like a^2 + b^2 = c^2, so in this case, 8^2 + 12^2 = c^2. Just crunch those numbers and you'll get the diagonal length. Easy peasy, right?
The diagonal measurement of an 8 ft square is: 11.31 feet.
I assume that you refer to a 12 ft x 12 ft 8 in square. The length of the diagonal is determined easily suing Pythororas's therem: Diagonal = sqrt[122 + (128/12)2] feet = sqrt(304.4... ) ft = 17.448 ft approx.
the square root of 128 or 8 times the square root of 2.
24 sq. ft. * * * * * The above answer must use some exotic units for measuring distance since 12 ft*8 feet is greater than 24 sq ft, and any of 12 feet*8 inches 12 inches*8 feet 12 inches*8 inches is smaller than 24 sq feet. It is not possible to give a more substantive answer since the measurement units are not given in the question.
Convert both units to feet and multiply: 12 in = 1 ft → 2 ft × 8 in = 2 ft × 8 ÷ 12 ft = 4/3 sq ft = 1⅓ sq ft ≈ 1.33 sq ft
The diagonal measurement of an 8 ft square is: 11.31 feet.
I assume that you refer to a 12 ft x 12 ft 8 in square. The length of the diagonal is determined easily suing Pythororas's therem: Diagonal = sqrt[122 + (128/12)2] feet = sqrt(304.4... ) ft = 17.448 ft approx.
To find the diagonal measurement of a square, you can use the Pythagorean theorem, which states that the square of the hypotenuse (the diagonal) is equal to the sum of the squares of the other two sides. In this case, the diagonal measurement would be the square root of (7^2 + 8^2) = √(49 + 64) = √113. Therefore, the diagonal measurement of a 7 ft by 8 ft square is approximately 10.63 feet.
Around 17.8. I did this with cossin, but check the answer with a calculator
17.8885'
The diagonal of an 8 ft by 10 ft square, by Pythagoras, would be sqrt(82 + 102) = sqrt(64+100) = sqrt(164) = 12.806 ft (to 5 sig figs)
The square has a diagonal measurement of: 1.13 km
(Diagonal)2 = (15)2 + (8)2 = (225) + (64) = 289Diagonal = sqrt(289) = 17
8 ft.
If you mean a rectangle then its diagonal using Pythagoras; theorem is 2 times the square root of 41 or about 12.806 feet rounded to 3 decimal places.
24 ft. wide, 8 ft. high, 4 ft. at the bottom- This is the standard measurement for a soccer net.
the square root of 128 or 8 times the square root of 2.