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Oh, dude, you're hitting me with the math questions now? Okay, okay, so if you wanna find the diagonal of an 8 ft by 12 ft rectangle, you can use the Pythagorean theorem. It's like a^2 + b^2 = c^2, so in this case, 8^2 + 12^2 = c^2. Just crunch those numbers and you'll get the diagonal length. Easy peasy, right?
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What is the diagonal measurement of an 8 ft square?
The diagonal measurement of an 8 ft square is: 11.31 feet.
How do you get diagonal measurement on a 12x12 8 feet highSQUARE?
I assume that you refer to a 12 ft x 12 ft 8 in square. The length of the diagonal is determined easily suing Pythororas's therem: Diagonal = sqrt[122 + (128/12)2] feet = sqrt(304.4... ) ft = 17.448 ft approx.
What is the diagonal measurement of a 8x8 square?
the square root of 128 or 8 times the square root of 2.
How many square feet are in a 12x8 area?
24 sq. ft. * * * * * The above answer must use some exotic units for measuring distance since 12 ft*8 feet is greater than 24 sq ft, and any of 12 feet*8 inches 12 inches*8 feet 12 inches*8 inches is smaller than 24 sq feet. It is not possible to give a more substantive answer since the measurement units are not given in the question.
How many sq ft is 2' x 8''?
Convert both units to feet and multiply: 12 in = 1 ft → 2 ft × 8 in = 2 ft × 8 ÷ 12 ft = 4/3 sq ft = 1⅓ sq ft ≈ 1.33 sq ft
