(x - 4y)(x + y)
-167
-3
3 - 3x + x2 - x3 = (1 - x)(x2 + 3)
x3 + x2 + 4x + 4 = (x2 + 4)(x + 1)
Factor x3 + x2 + 2x + 2, by grouping. Group the first two terms and the last two terms. Then factor. First, factor x3 + x2 by pulling out an x2 term: x2(x + 1) Second, factor 2x + 2 by pulling out a 2: 2(x + 1) So, you now have: x2(x + 1) + 2(x + 1) If you have factored correctly, the terms inside the parentheses should be the same. Now regroup. ANS: (x + 1)(x2 + 2)
(x + 3y)(x2 - 3xy + 9y2)
Multiply them together.
x3+27y3 = (x+3y) · (x2-3xy+9y2)
x2-49 = (x-7)(x+7)
If you're looking to factor this expression, then you need to find two values that add up -20, and which multiply to make 4. Unfortunately, no such terms exist, so this expression can not be factored.
First it would be easiest to factor out the 2. 2x2-8y2 2(x2-4y2) Then you factor the part in the parenthesis as follows 2(x-2y)(x-2y) which can be simplified as 2(x-2y)2
(x + 6y)(x - 3y)
L2 math.
x2 + 13x + 36 = (x + 9)(x + 4)
(x2 + 1)(x2 - 2)
x3+8y3 = (x+2y)(x2-2xy+4y2) The discriminant of the quadratic factor is 4y2-16y2 < 0 so there are no real roots. So the only real root of the original polynomial is x+2y=0 or x = -2y
x2 + 6x + 5 can be factored into (x+1) (x+5)