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What else can I help you with?
How do you factor 4x squared - 7x cubed equals?
-3
Factor the expression x2 - 169?
-167
Factor by grouping 3-3x plus x2-x3?
3 - 3x + x2 - x3 = (1 - x)(x2 + 3)
What is the factor of x3 plus x2 plus 4x plus 4?
x3 + x2 + 4x + 4 = (x2 + 4)(x + 1)
Factor X cubed plus x squared plus 2x plus 2?
Factor x3 + x2 + 2x + 2, by grouping. Group the first two terms and the last two terms. Then factor. First, factor x3 + x2 by pulling out an x2 term: x2(x + 1) Second, factor 2x + 2 by pulling out a 2: 2(x + 1) So, you now have: x2(x + 1) + 2(x + 1) If you have factored correctly, the terms inside the parentheses should be the same. Now regroup. ANS: (x + 1)(x2 + 2)
How do you factor completely x3 27y3?
(x + 3y)(x2 - 3xy + 9y2)
How do you find the area of a whiteboard with one side being x 2y and the other side being x2 3xy-4y2?
Multiply them together.
What is a factor of x3 plus 27y3?
x3+27y3 = (x+3y) · (x2-3xy+9y2)
What is the answer to x2-49 when you completely factor?
x2-49 = (x-7)(x+7)
How do you find the solution to x2 - 20xy plus 4y2?
If you're looking to factor this expression, then you need to find two values that add up -20, and which multiply to make 4. Unfortunately, no such terms exist, so this expression can not be factored.
How do you factor 2x2-8y2?
First it would be easiest to factor out the 2. 2x2-8y2 2(x2-4y2) Then you factor the part in the parenthesis as follows 2(x-2y)(x-2y) which can be simplified as 2(x-2y)2
X2 plus 3xy - 18y2 equals?
(x + 6y)(x - 3y)
How do you factor x2-8x equals 16 completely?
L2 math.
How do you factor completely x to the fourth power minus x squared minus 2?
(x2 + 1)(x2 - 2)
In solving polynomials x cubed plus 8 y cubed?
x3+8y3 = (x+2y)(x2-2xy+4y2) The discriminant of the quadratic factor is 4y2-16y2 < 0 so there are no real roots. So the only real root of the original polynomial is x+2y=0 or x = -2y
Factor completely x2 plus 6x plus 5?
x2 + 6x + 5 can be factored into (x+1) (x+5)
What conic section does the equation x2 4y2 6x 8y plus 1 equals 0 represent?
hyperbola
