(x + 3y)(x2 - 3xy + 9y2)
Multiply them together.
x3+27y3 = (x+3y) · (x2-3xy+9y2)
x2-49 = (x-7)(x+7)
If you're looking to factor this expression, then you need to find two values that add up -20, and which multiply to make 4. Unfortunately, no such terms exist, so this expression can not be factored.
First it would be easiest to factor out the 2. 2x2-8y2 2(x2-4y2) Then you factor the part in the parenthesis as follows 2(x-2y)(x-2y) which can be simplified as 2(x-2y)2
(x + 6y)(x - 3y)
L2 math.
x2 + 13x + 36 = (x + 9)(x + 4)
(x2 + 1)(x2 - 2)
x3+8y3 = (x+2y)(x2-2xy+4y2) The discriminant of the quadratic factor is 4y2-16y2 < 0 so there are no real roots. So the only real root of the original polynomial is x+2y=0 or x = -2y
x2 + 6x + 5 can be factored into (x+1) (x+5)