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You have this equation:
x2 - 12y = 0
First, move the term with y to the right side using addition:
x2 = 12y
Now, divide both sides by 12, so y is by itself:
x2/12 = y
From here, you can use the properties of a parabola (y = x2), "flattening" it so that it is 1/12 of the usual height. You can start with the fact that a parabola is symmetrical over the y-axis-- the vertical line through the point (0,0)-- and passes through the point (0,0). From that point, it gradually turns upward as it moves away from (0,0), passing through the points (1, 1/12), (2, 4/12), (3, 9/12), and so on.
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How many x-intercepts does the graph of y equals x2 have?
Just one. It's at the origin. (0, 0)
What are the x and and y intercepts for the graph of 2x - 5y equals 10?
x intercept = (5, 0) y intercept = (0, -2)
How do you graph an equation written in y equals mx plus b form?
You draw a straight line through (0,b) which has a slope of m.
Graph the function fx equals -4?
The graph of the function f(x) = 4, is the horizontal line to the x=axis, which passes through (0, 4). The domain of f is all real numbers, and the range is 4.
Graph x equals y plus 2?
x=y+2 y=x-2 The y value at the x axis (x=0) will be -2, so graph (0, -2). Let's calculate a few more points by varying x and calculating y: if x=2, y=2-2=0 (2, 0) similarly: (1, -1) (5, 3) Graph those points, then draw a line connecting them all. That's the graph of x=y+2.
