t3-1/27
(x + 2)(3x - 1)(3x + 1)
Find factors of -5 that can be added to make -4, in this case -5 and 1, so: (x - 5)(x + 1) = x2 - 4x - 5
xcubed-1 Answer::(X-1)(Xsquared+X+1) when you factor xcubed minus a number its the same thing as x cubed minus y cubed and x cubed minus y cubed factors to:: (x-y)(xsquared+xy+y squared) the first factor, (x-y), is the cubed root of the first and the cubed root of the second, so in the answer i have (x-1), which is x cubed minus one cubed :) the second factor, (xsquared+xy+ysquared), you take the first number squared, Xsquared, then the first and second one multiplied together, XY, and then the second number squared, Ysquared, so in the answer i have (xsquared+x+1), which is x squared, then x times 1 which is just x, and positive 1, which is negative 1 squared :) x^3 - 1
x3 - 4x2 + x + 6 = (x + 1)(x - 2)(x - 3)
64 x cubed minus y cubed is (4x - y)(16x^2 + 4xy + y^2)
(x - 4)(x^2 + 4x + 16)
5x^2(4x - 5)(5x + 11)
x2 - 4x - 21 = (x-7)(x+3)
x(x + 3)(x - 4)
x cubed minus 216
(x - 1)(x - 1)(x - 1) - (x + 1)(x + 1)(x + 1)
Factor out the GCF and get X(X2-X+1).
x(x + 1)(x -1)
(x - 1)(x^2 + x + 1)
(x - 2)(x^2 + x + 3)
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