No. The mean is the expected value of the random variable but you can also have expected values of functions of the random variable. If you define X as the random variable representing the result of a single throw of a fair die, the expected value of X is 3.5, the mean of the probability distribution of X. However, you play a game where you pay someone a certain amount of money for each throw of the die and the other person pays you your "winnings" which depend on the outcome of the throw. The variable, "your winnings", will also have an expected value. As will your opponent's winnings.
The formula to find the value of X would be Y-2X. This would equal to y-9 times 2 X.
No. The expected value is the mean!
The expected value is the average of a probability distribution. It is the value that can be expected to occur on the average, in the long run.
x is a variable. You do not have to know what its value is. In that equation you have to find the value of x, so if you already know what x stands for then you know the answer
Follow these steps:Find all the values that the random variable (RV) can take, x.For each x, find the probability that the RV takes than value, p(x).Multiply them: x*p(x).Sum these over all possible values of x.The above sum is the expected value of the RV, X.
The expected value of a Martingale system is the last observed value.
If X takes the value 1 with probability p and 0 with probability (1-p), and there are n independent trials then E(X) = np
If a random variable X is distributed normally with probability distribution function p(x), then the expected value of X is E(X) = integral of x*p(x)dx evaluated over the whole of the real line.
The deviation is the observed value less the expected value.
No. The mean is the expected value of the random variable but you can also have expected values of functions of the random variable. If you define X as the random variable representing the result of a single throw of a fair die, the expected value of X is 3.5, the mean of the probability distribution of X. However, you play a game where you pay someone a certain amount of money for each throw of the die and the other person pays you your "winnings" which depend on the outcome of the throw. The variable, "your winnings", will also have an expected value. As will your opponent's winnings.
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E(X+Y)=E(X)+E(Y)where E(X)=population mean
180-x...... hahaahahaaa
The chi-squared test is used to compare the observed results with the expected results. If expected and observed values are equal then chi-squared will be equal to zero. If chi-squared is equal to zero or very small, then the expected and observed values are close. Calculating the chi-squared value allows one to determine if there is a statistical significance between the observed and expected values. The formula for chi-squared is: X^2 = sum((observed - expected)^2 / expected) Using the degrees of freedom, use a table to determine the critical value. If X^2 > critical value, then there is a statistically significant difference between the observed and expected values. If X^2 < critical value, there there is no statistically significant difference between the observed and expected values.
The formula to find the value of X would be Y-2X. This would equal to y-9 times 2 X.
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