This is an expression. Equations can be graphed, not expressions. Let's assume that the equation was supposed to be 3x-y-2 = 0
First, re-arrange so that y is isolated: y = 3x-2
Then plug in x values
Ex, x=1, so y=3(1)-2=1
x=2, so y=3(2)-2=4
So you have two points, (1,1) and (2,4)
Plot them both and since this is a linear graph, you can draw a straight line between the two points, continuing throughout the entire graph.
4
If you mean: y = -3x then the slope is -3 and there is no y intercept
Substitute the point into the equation, eg. if you have point (1,2) and equation y=3x+7 you get 2=3*1+7 =10 2 doesnt equal 10, so (1,2) isn't on the graph y=3x+7
(a) y = -3x + 1
x intercept = (5, 0) y intercept = (0, -2)
1
y-3x-3 y=3x+3 A line with a slope of 3 crossing the y-axis at 3.
If you mean: y = 3x+2 then the parallel line will be y = 3x-3
5
4
In order to graph this equation, you have to isolate y. 3x + 5y = -2 3x + 5y + 2 = 0 3x + 2 = -5y (3x+2)/-5 = y Now you can plug it into a graphing calculator. If you're graphing by hand, the equation you'll want to use is: (-3/5)x - (2/5) = y So the slope will be negative 3/5 and the y-intercept is -2/5.
If you mean: y = -3x then the slope is -3 and there is no y intercept
-2
2
The starting point on the y-axis changes from -2 to 6.
y=7-3x
The graph of [ y = -3x ] is a straight line, through the origin, with slope of -3 .