You never "move" things "to the other side" of an equation. The only
permissible treatment of an equation is to perform the same operation
on both sides.
Let's have a look at this one:
(x)-0.5 = 1
A negative exponent means the reciprocal of the positive one,
so you can write:
1/(x)0.5 = 1
You haven't changed anything or performed any operation, only
written the left side in a different way.
Now it's time to think about the meaning of an exponent of 1/2 .
It means "square root", so there's another way to write the left side:
1/sqrt(x) = 1
We still haven't performed any operations, only found different ways
to write the left side. Now we can do some operations to solve for 'x'.
Multiply each side of the equation by sqrt(x):
1 = sqrt(x)
Square both sides of the equation:
1 = x
What was so mysterious or complicated about that ?
A number to a negative power is equal to One divided by number to its positive power. So, x^-2 is equal to 1/x2.
x2=-81take the square root of both sidessince 81 is negative you need to take 81 times i when i=-1 then solve as the square root of 81. your answer is x=9i
if p² = 169, then p = ±√169 In other words, take the square root of 169 and p is either the positive or negative value of the square root.
E is energy and MC2 is matter used to the second power... now you solve it
11×11×11=1331 You would solve this by showing 11, 11 times.
8 1/3 = ab^-1, 1.8 =ab^2
w = 70.25
Your question is not very clear. Are you asking: solve for x where negative 4 over x equals negative 20. x equals 1/5 (one fifth)
y = 2 (Divide each side of the equation by -45)
Adding a negative number to a negative number makes a larger negative. In order to solve this you add the numbers together as a positive then add a negative sign.
-5x2 = -75 x2 = 25 x = ±sqrt( 25 ) x = ±___
30
88
A number to a negative power is equal to One divided by number to its positive power. So, x^-2 is equal to 1/x2.
Question 3C: Four minus seven equals negative two.
By elimination: x = 3 and y = 0
b = 14