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I assume you mean degrees Fahrenheit.

First you must remove heat to make ice not add it. Next, the amount depends largely on the quantity (mass) of water being frozen.

Water has a enthalpy of fusion of 333.55 KJ / Kg

This means that for each kilogram of water you must remove 333.55 kilo-Joules to make it into ice.

A conversion factor of 1 : 0.9478 between KJ and BTU gives us 316.14 BTU per Kilogram of water.

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Q: How many BTU's does it take to turn 32 degree water into 32 degree ice?
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212 - 80 = 132 degrees temperature increase x 1 pound water = 132 BTU


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How many btus does it take to raise of 5 pounds of water to 5 degrees Fahrenheit?

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How many BTUs does it take to raise the temperature of water from 32 degrees to 300 degrees?

That will completely depend on how much water there is.


How many BTUs will it take to change 1 gallon of water at 32 degrees to ice at 32 degrees?

You would need to remove approximately 1200 BTUs of heat to convert a gallon of water to ice. There are 8.34 lb in a gallon of water, which converting to lb-moles is 0.463. The latent heat of crystallization for water is -2583.4 BTU/lb-mole. Multiplying the two together and you get -1197 BTUs, which means you need to remove that amount of heat to convert the gallon of water to ice.


Why does it take fewer btus to change 1 lb of 0 degree ice into 32 degree ice than it does to change 1lb of 32 degree ice into 32 degree water?

In a solid state, the molecules are bound together; these bonds must be broken to convert the substance from solid to liquid, and that requires energy.


How many btus are required to change one pound of ice at 20 degrees Fahrenheit to steam at 220 degrees Fahrenheit?

1)This is a 5 part question. The first is realizing that 20F to 32F uses .5BTU per pound per degree. That means it takes 32-20=12*.5=6BTUs to get the ice to 32F. 2)Then you need to know the Latent Heat of Fusion for Ice which is 144BTUs (given). Lets assumes the ice changes from ice to water instantaneously at 32F. 3)Next we calculate the BTUs from 32F to 212F. Which is 1BTU per pound per degree F. 212-32=180 so it take 180BTUS. 4)Next we have to use the Latent Heat of Vaporization of water which will say instantaneously converts water to vapor. This takes 970BTUS (given). 5)Then we calculate the BTUS from 212F to 220F. Which is .5BTUs per pound per degree F which is 220-212=8*.5=4BTUs...... Finally add up all the BTUs and you get 6+144+180+970+4=1304BTUs.


How many BTUs does it take to heat 390 gallon tank of water from 60 degrees to 248 degrees?

The specific heat of water is 1 BTU per pound per degree Fahrenheit. There are 8.3378 lbs/gallon at 60 degrees, which equals 3251.742 pounds of water. The number of BTUs to raise it 188 degrees is then 611,327.496 BTUs.


How many btus does it take to heat up one gallon of water?

That depends on what the starting temperature of the water is,and what temperature you want it to reach.If you expect to get a number, you must first give the necessary numbers.


How many btus are required to change one pound of ice at 20 degree Fahrenheit to steam at 220 degree Fahrenheit?

1)This is a 5 part question. The first is realizing that 20F to 32F uses .5BTU per pound per degree. That means it takes 32-20=12*.5=6BTUs to get the ice to 32F. 2)Then you need to know the Latent Heat of Fusion for Ice which is 144BTUs (given). Lets assumes the ice changes from ice to water instantaneously at 32F. 3)Next we calculate the BTUs from 32F to 212F. Which is 1BTU per pound per degree F. 212-32=180 so it take 180BTUS. 4)Next we have to use the Latent Heat of Vaporization of water which will say instantaneously converts water to vapor. This takes 970BTUS (given). 5)Then we calculate the BTUS from 212F to 220F. Which is .5BTUs per pound per degree F which is 220-212=8*.5=4BTUs...... Finally add up all the BTUs and you get 6+144+180+970+4=1304BTUs.