I assume you mean degrees Fahrenheit.
First you must remove heat to make ice not add it. Next, the amount depends largely on the quantity (mass) of water being frozen.
Water has a enthalpy of fusion of 333.55 KJ / Kg
This means that for each kilogram of water you must remove 333.55 kilo-Joules to make it into ice.
A conversion factor of 1 : 0.9478 between KJ and BTU gives us 316.14 BTU per Kilogram of water.
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1 BTU = heat corresponding to change in temperature of 1 pound of water by 1° Fahrenheit.Weight of 1 gallon of water = roughly 8.33 poundsHeat corresponding to change in temperature of 1 gallon of water by 1° Fahrenheit = 8.33 BTU.But it doesn't take that, i.e. you don't have to supply it. You're talking about lowering thetemperature, so you're just allowing the water to cool on its own. As it does, it releases8.33 BTU of heat, which you can then collect and take away to use somewhere else.
It takes 1000 calories to heat 1 litre of water 1 degree C.
If you're in Celsius, 13459.5 Btu's. If you're in Fahrenheit, 12632.5 Btu's.
Not sure exactly what you are asking but it takes 1 btu to raise the temprerature of 1 pound of water by 1 degree F. ( 4.2 joules to raise 1 lb by 1 degree Celsius ) so it depends on how much water we are talking about. there is also a transition to boiling where the water has reached 212 'F and has not yet begun to boil... it then takes an additional 970.3 btu's ( per lb ) for the water to achieve boiling, this is called the latent heat of vapourization .. hope this helps
212 - 80 = 132 degrees temperature increase x 1 pound water = 132 BTU
1320 btu`s
One BTU is the energy required to raise one pound of water by one degrees. Therefore, your answer would be one half.
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2250
That will completely depend on how much water there is.
You would need to remove approximately 1200 BTUs of heat to convert a gallon of water to ice. There are 8.34 lb in a gallon of water, which converting to lb-moles is 0.463. The latent heat of crystallization for water is -2583.4 BTU/lb-mole. Multiplying the two together and you get -1197 BTUs, which means you need to remove that amount of heat to convert the gallon of water to ice.
In a solid state, the molecules are bound together; these bonds must be broken to convert the substance from solid to liquid, and that requires energy.
1)This is a 5 part question. The first is realizing that 20F to 32F uses .5BTU per pound per degree. That means it takes 32-20=12*.5=6BTUs to get the ice to 32F. 2)Then you need to know the Latent Heat of Fusion for Ice which is 144BTUs (given). Lets assumes the ice changes from ice to water instantaneously at 32F. 3)Next we calculate the BTUs from 32F to 212F. Which is 1BTU per pound per degree F. 212-32=180 so it take 180BTUS. 4)Next we have to use the Latent Heat of Vaporization of water which will say instantaneously converts water to vapor. This takes 970BTUS (given). 5)Then we calculate the BTUS from 212F to 220F. Which is .5BTUs per pound per degree F which is 220-212=8*.5=4BTUs...... Finally add up all the BTUs and you get 6+144+180+970+4=1304BTUs.
The specific heat of water is 1 BTU per pound per degree Fahrenheit. There are 8.3378 lbs/gallon at 60 degrees, which equals 3251.742 pounds of water. The number of BTUs to raise it 188 degrees is then 611,327.496 BTUs.
That depends on what the starting temperature of the water is,and what temperature you want it to reach.If you expect to get a number, you must first give the necessary numbers.
1)This is a 5 part question. The first is realizing that 20F to 32F uses .5BTU per pound per degree. That means it takes 32-20=12*.5=6BTUs to get the ice to 32F. 2)Then you need to know the Latent Heat of Fusion for Ice which is 144BTUs (given). Lets assumes the ice changes from ice to water instantaneously at 32F. 3)Next we calculate the BTUs from 32F to 212F. Which is 1BTU per pound per degree F. 212-32=180 so it take 180BTUS. 4)Next we have to use the Latent Heat of Vaporization of water which will say instantaneously converts water to vapor. This takes 970BTUS (given). 5)Then we calculate the BTUS from 212F to 220F. Which is .5BTUs per pound per degree F which is 220-212=8*.5=4BTUs...... Finally add up all the BTUs and you get 6+144+180+970+4=1304BTUs.