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How many combinations of the numbers 1 2 and 3 using each digit only can I get?
Wiki User
∙ 15y ago
If you must use each digit once, and only once, then there are 3 ways to pick the first digit, and 2 way to pick the second. This then leaves only 1 number available for third place, so there is no choice for it. 3 multiplied by 2, multiplied by 1 = 6
123
132
213
231
312
321
If you don't have to use each digit very time, but still cannot repeat a digit then there are 9 extra choices available. 012
013 021
023 031
032 001
002
003
Wiki User
∙ 15y ago
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How many 3 digit combinations are there in the numbers 1 to 9?
It depends. If you can only use each number once, there are 720 combinations. If you can use numbers multiple times, then there are 1000 combinations, by using all numbers from 000 to 999.
How many 5 digit combos in 30 numbers?
The answer will depend on how many digits there are in each of the 30 numbers. If the 30 numbers are all 6-digit numbers then the answer is NONE! If the 30 numbers are the first 30 counting numbers then there are 126 combinations of five 1-digit numbers, 1764 combinations of three 1-digit numbers and one 2-digit number, and 1710 combinations of one 1-digit number and two 2-digit numbers. That makes a total of 3600 5-digit combinations.
How many combinations the numbers one two and three using each digit only once can I get?
6 - 123, 132, 213, 231, 312, and 321.
If using numbers 0 through 9 how many different 4 digit combinations can be made with no restrictions on order or repeats?
In other words, how many 4 digit combination locks are there using the digits 0-9 on each wheel. There are 10×10×10×10 = 10⁴ = 10,000 such combinations.
What are all the possibilities of 4-digit numbers from numbers 0-9?
There are 10,000 possible combinations, if each number can be used more than once.
How many 4 digit combinations can be made using numbers 1 2 3 4 6?
120 combinations using each digit once per combination. There are 625 combinations if you can repeat the digits.
How many 3 digit combinations are there in the numbers 1 to 9?
It depends. If you can only use each number once, there are 720 combinations. If you can use numbers multiple times, then there are 1000 combinations, by using all numbers from 000 to 999.
If using numbers 1 through 9 how many different 4 digit combinations can be made with no restrictions on order or repeats?
Each digit can appear in each of the 4 positions. There are 9 digits, therefore there are 9⁴ = 6561 such combinations.
How many 5 digit combos in 30 numbers?
The answer will depend on how many digits there are in each of the 30 numbers. If the 30 numbers are all 6-digit numbers then the answer is NONE! If the 30 numbers are the first 30 counting numbers then there are 126 combinations of five 1-digit numbers, 1764 combinations of three 1-digit numbers and one 2-digit number, and 1710 combinations of one 1-digit number and two 2-digit numbers. That makes a total of 3600 5-digit combinations.
How many combinations the numbers one two and three using each digit only once can I get?
6 - 123, 132, 213, 231, 312, and 321.
How many combinations of 6 digits can be made from the numbers 1 - 6 using each digit upto 6 times each per combination?
The right answer is 2763633600 by amar nirania
What is a list of 5 digit combinations starting with a 3 and numbers can be repeated?
The number of four-digit combinations is 10,000 .Stick a '3' before each of them, and you have all the possible 5-digit combinations that start with 3.There are 10,000 of them. They run from 30,000 to 39,999 .
If using numbers 0 through 9 how many different 4 digit combinations can be made with no restrictions on order or repeats?
In other words, how many 4 digit combination locks are there using the digits 0-9 on each wheel. There are 10×10×10×10 = 10⁴ = 10,000 such combinations.
How many 4 digit numbers combinations can be made using 1234567?
Not repeating, it is 7*6*5*4 which is 840 ways ---- There are 7 choices for each of four digits, right? 74 = 2401
How many 7 digit combinations can you have if you can only use the numbers 0 through 9 once each?
10!/3! = 604800 different combinations.
If using numbers 0 through 9 how many different 3 digit combinations can be made?
There are 10 possible digits that can be used: 0, 1, 2, 3, 4, 5, 6, 7, 8, 9. If you can only use each digit once, there are 10 choices for the first digit, 9 remaining choices for the second digit, and 8 remaining choices for the final digit - 10 x 9 x 8 = 720 combinations. If you can use each digit repeatedly, you have 10 choices for each digit - 10 x 10 x 10 = 1000 combinations.
How many 4 digit combinations using 0-9 if each number may be used more than once?
10,000 combinations.
