This kind of problem is called permutations.
First, choose one of the 10 numbers: 10 choices here.
Then, choose one of the 9 remaining numbers: 9 choices, and etc.
10 * 9 * 8 * 7 * 6 * 5 * 4 * 3 * 2 * 1 = 3628800.
Or, if repeats are allowed, then we have:
10 * 10 * 10 * 10 * 10 * 10 * 10 * 10 * 10 * 10 = 1010 = 10000000000.
You can make 5 combinations of 1 number, 10 combinations of 2 numbers, 10 combinations of 3 numbers, 5 combinations of 4 numbers, and 1 combinations of 5 number. 31 in all.
Only one.
There are 45 combinations.
There are 15 combinations.
There are 13,244 of them.
You can make 5 combinations of 1 number, 10 combinations of 2 numbers, 10 combinations of 3 numbers, 5 combinations of 4 numbers, and 1 combinations of 5 number. 31 in all.
Only one.
14 * * * * * Wrong! There are 15. 4 combinations of 1 number, 6 combinations of 2 number, 4 combinations of 3 numbers, and 1 combination of 4 numbers.
Assuming that the six numbers are different, the answer is 15.
9000
252 combinations, :)
35
None. You do not have enough numbers to make even one combination.
The rearrangement of 5 figure numbers will be 5x4x3x2x1 which is 120 combinations, when you don't repeat a number.
There are 8,592,039,666 combinations of 6 numbers out of 138 numbers, like the numbers from 1 to 138.
There are a huge number of combinations of 5 numbers when using the numbers 0 through 10. There are 10 to the 5th power combinations of these numbers.
There are infinitely many numbers and so infinitely many possible combinations.