If you assume that the punter is in space, where there is no gravity nor air resistance, it will take 2/3 second.
20 meters per second
23 sec
If the arrow was fired in a direction making an angle x with the horizontal, and assuming that acceleration due to gravity is 32 feet per second^2 ijn the downward direction, then its height at time t iss(t) = 160*sin(x)*t - 16*t^2.
The acceleration of gravity is 9.8 meters per second2 downward. 1.6 seconds after falling from a branch near the surface of the Earth, the apple's speed is 15.68 meters per second. It's velocity is 15.68 meters per second downward. The tree has to be really tall, since the apple falls 12.544 meters (about 41 feet) in 1.6 seconds.
16.66 meters per second
Acceleration of the arrow is -3m/s2A = (velocity minus initial velocity) / time
To find the distance traveled, we can use the formula: distance = initial velocity * time + 0.5 * acceleration * time^2. The initial velocity is 75 miles per second, the final velocity is 145 miles per second, and the time is 15 seconds. The acceleration can be found using the formula: acceleration = (final velocity - initial velocity) / time. Plug in the values to find the acceleration and then calculate the distance traveled in 15 seconds.
The acceleration of the car can be calculated using the formula: acceleration = (final velocity - initial velocity) / time. Given the initial velocity (A), final velocity (B), and time (8 seconds), you can substitute the values into the formula to find the acceleration.
the answer is 24-9 m/sec. yuor welcome
Assuming you release it from a position of rest, you must multiply the time by the acceleration. The acceleration due to gravity near Earth's surface is approximately 9.8 meters/second squared.
The train's velocity after 30 seconds can be calculated using the formula: final velocity = initial velocity + (acceleration * time). Plugging in the values, final velocity = 20 km/hr + (4 km/hr/s * 30 s) = 20 km/hr + 120 km/hr = 140 km/hr. So, the train's velocity after 30 seconds is 140 km/hr.
The sprinter's velocity at 1.2 seconds can be calculated using the formula: velocity = initial velocity + acceleration × time. Given the initial velocity is 0 m/s, acceleration is 2.3 m/s^2, and time is 1.2 seconds, the velocity at 1.2 seconds would be 2.76 m/s.
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Since the bullet is fired straight upward, it will be decelerating due to gravity acting in the opposite direction of its initial velocity. Thus, at t = 3 seconds, the velocity will be less than 36ft per second but still positive (as it's moving upward). To calculate the exact velocity, you would need to use the kinematic equation for velocity in one dimension.
The velocity gained by the aircraft in 4 seconds can be calculated using the formula: velocity = acceleration × time. Given acceleration of 3 m/s^2 and time of 4 seconds, the velocity gained by the aircraft would be 12 meters per second.
The speed (magnitude of velocity) is always 9.8 meters per second (32.2 feet per second) greater than it was exactly one second earlier. If the object spent "N" seconds falling, then its speed (magnitude of velocity) is 9.8N meters per second (32.2N feet per second) greater at the bottom than it was at the top. The direction of velocity remains constant under the influence of gravity ... straight down.
a=change over velocity/time 60-initial velocity 45-final velocity 45-60= 15m/s 15/5= 3- acceleration