If you assume that the punter is in space, where there is no gravity nor air resistance, it will take 2/3 second.
20 meters per second
23 sec
If the arrow was fired in a direction making an angle x with the horizontal, and assuming that acceleration due to gravity is 32 feet per second^2 ijn the downward direction, then its height at time t iss(t) = 160*sin(x)*t - 16*t^2.
The acceleration of gravity is 9.8 meters per second2 downward. 1.6 seconds after falling from a branch near the surface of the Earth, the apple's speed is 15.68 meters per second. It's velocity is 15.68 meters per second downward. The tree has to be really tall, since the apple falls 12.544 meters (about 41 feet) in 1.6 seconds.
16.66 meters per second
Acceleration of the arrow is -3m/s2A = (velocity minus initial velocity) / time
the answer is 24-9 m/sec. yuor welcome
The initial velocity is 0 metres/second.
A ball thrown vertically upward returns to the starting point in 8 seconds.-- Its velocity was upward for 4 seconds and downward for the other 4 seconds.-- Its velocity was zero at the turning point, exactly 4 seconds after leaving the hand.-- During the first 4 seconds, gravitational acceleration reduced the magnitude of its upward velocity by(9.8 meters/second2) x (4 seconds) = 39.2 meters per second-- So that had to be the magnitude of its initial upward velocity.
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I am assuming the initial speed is 6.2 m/s Let upward motion be positive! Gravity decreases the speed by 9.8 m/s each second Acceleration due to gravity = -9.8 m/s each second (negative because gravity accelerates objects downward) Find time to reach the top of the path! Final velocity at the top = 0 m/s Initial velocity = 6.2 m/s Final velocity = Initial velocity + acceleration * time Time - = (final velocity - initial velocity) ÷ acceleration Time = (0 - 6.2) ÷ -9.8 = 0.633 seconds (to reach top) The path is symmetrical. 0.633 seconds to reach top and 0.633 seconds to reach glove again. Total time = 12.66 seconds
a=change over velocity/time 60-initial velocity 45-final velocity 45-60= 15m/s 15/5= 3- acceleration
It will depend upon the initial velocity of the body. If 'u' be the initial velocity of the body, then the final velocity will be: v = u + at (v = final velocity, a = acceleration, t = time) i.e., v=u+10*7 = (u + 70) m/sec. If u=0 (i.e the initial velocity be zero) then final velocity, v=70 m/sec.
Initial velocity can be measured in the same units as any other velocity. In SI, that would be meters per second, but often km / hour are used, or (in a minority of countries) feet/second or miles/hour.
Linear Velocity = Initial Velocity (m/s) + Acceleration (m/s2) * t 43.2 km/h
anything shot up with that initial velocity. There isn't anything in specific.
You throw a ball straight up with a velocity of 40 meters per second. What is the ball's velocity after 3 seconds?