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# You could use the Pythagorean theorem (a2+b2=c2) if you have the measurements of the other two sides. # If the triangle is a right triangle, and you have either the measurement of one of the sides and the angle of one of the sides, then you can use sine, cosine, or tangent to find it. Other than that, I am not sure if it is mathematically possible.
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A rectangle and a triangle have equal areas The length of the rectangle is 12 inches and its width is 8 inches If the base of the triangle is 32 inches what is the length in inches altitude drwn to ba?
A rectangle and a triangle have equal areas. The length of the rectangle is 12 inches, and its width is 8 inches. If the base of the triangle is 32 inches, what is the length, in inches, of the altitude drawn to the base? WRONG WRONG WRONG NO NO NO ::"::":""::":"""::"":":""::::::::::::: ::"::": ::":: :: ::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::"
What is the length of a rectangle that has a width of 8 centimeters and an area of 256 square centimeters?
If the area of a rectangle is found by measuring the length times the width, then if you know the area is 256 and the width is 8, you find the length by dividing 256 by 8 which would give you a length of 32 centimeters.
The length of a rectangle is 3 inches more than its width and its perimeter is 22 inches Find the width of the rectangle?
Perimeter = length + width + length + width = 2 x (length + width) Given: perimeter = 22in length = width + 3in Thus 22 = 2 x (width + 3 + width) 11 = 2 x width + 3 8 = 2 x width 4 = width So the width is 4in.
The length of a rectangle is twice the width width the perimeter is 48 in find the dimensions of the rectangle?
Let the width of the rectangle be represented by "w" inches. Since the length is twice the width, it can be expressed as "2w" inches. The formula for the perimeter of a rectangle is P = 2(l + w), where P is the perimeter, l is the length, and w is the width. Substituting the given values into the formula, we get 48 = 2(2w + w). Simplifying, we find that 48 = 6w. Solving for w, we find that the width of the rectangle is 8 inches, and the length is 16 inches.
Find the length of a leg of an isosceles right triangle whose hypotenuse measures 8 radical 2?
the answer is 8
What is the area of a triangle if its length is 14 and its width is 8?
Assuming a right-angle triangle whose length is vertical, and the width is the base, then (14×8) ÷ 2 = 56 square units.
A rectangle and triangle have equal areas the length of the rectangle is 12 in and its width is 8 in if the base of the triangle is 32 in what is the length in inches of the altitude drawn to the base?
A rectangle and a triangle have equal areas. The length of the rectangle is 12 inches, and its width is 8 inches. If the base of the triangle is 32 inches, what is the length, in inches, of the altitude drawn to the base?
How do you find the length and width of a rectangle?
the length of a rectangle is 8 more than the width. the area os 345 centimeters. find the length and width of the rectangle
A rectangle and a triangle have equal areas The length of the rectangle is 12 inches and its width is 8 inches If the base of the triangle is 32 inches what is the length in inches altitude drwn to ba?
A rectangle and a triangle have equal areas. The length of the rectangle is 12 inches, and its width is 8 inches. If the base of the triangle is 32 inches, what is the length, in inches, of the altitude drawn to the base? WRONG WRONG WRONG NO NO NO ::"::":""::":"""::"":":""::::::::::::: ::"::": ::":: :: ::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::"
Find the length of the hypotenuse of a right triangle whose legs are 8 and 15 units in length?
Find the length of the hypotenuse of a right triangle whose legs are 8 and 15 units in length.
A rectangle and a triangle have equal areas The length of the rectangle is 12 inches and its width is 8 inches If the base of the triangle is 32 inches what is the length in inches of the alt?
6
A rectangle and a triangle have equal areas The length of the rectangle is 12 inches and its width is 8 inches If the base of the triangle is 32 inches what is the length in inches of the altitu?
6
Perimeter of a rectangle is 40 ft The width is 8 feet less find the length?
Perimeter = 2*(Width + Length) So 40 = 2*(8 + Length) 20 = 8 + Length Length = 12.
The width of a rectangle is 2ft less than the length The area is 8 ft squared Find the length and the width?
Easy. Width = 2ft, Length = 4 ft, therefore the Area = 8 ft.
A rectangle and a triangle have equal areas The length of the rectangle is 12 inches and its width is 8 inches If the base of the triangle is 32 inches what is the length in inches of the altitude dra?
6
A rectangle and a triangle have equal areas The length of the rectangle is 12 inches and its width is 8 inches If the base of the triangle is 32 inches what is the length in inches of the altiitude dr?
6 inches
What is the length of a rectangle that has a width of 8 centimeters and an area of 256 square centimeters?
If the area of a rectangle is found by measuring the length times the width, then if you know the area is 256 and the width is 8, you find the length by dividing 256 by 8 which would give you a length of 32 centimeters.
