# You could use the Pythagorean theorem (a2+b2=c2) if you have the measurements of the other two sides. # If the triangle is a right triangle, and you have either the measurement of one of the sides and the angle of one of the sides, then you can use sine, cosine, or tangent to find it. Other than that, I am not sure if it is mathematically possible.
A rectangle and a triangle have equal areas. The length of the rectangle is 12 inches, and its width is 8 inches. If the base of the triangle is 32 inches, what is the length, in inches, of the altitude drawn to the base? WRONG WRONG WRONG NO NO NO ::"::":""::":"""::"":":""::::::::::::: ::"::": ::":: :: ::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::"
If the length of a rectangle is twice its width and it has a perimeter of 48, then the rectangle is 16 in length and 8 in width.
If the area of a rectangle is found by measuring the length times the width, then if you know the area is 256 and the width is 8, you find the length by dividing 256 by 8 which would give you a length of 32 centimeters.
Perimeter = length + width + length + width = 2 x (length + width) Given: perimeter = 22in length = width + 3in Thus 22 = 2 x (width + 3 + width) 11 = 2 x width + 3 8 = 2 x width 4 = width So the width is 4in.
8x4x2
Assuming a right-angle triangle whose length is vertical, and the width is the base, then (14×8) ÷ 2 = 56 square units.
A rectangle and a triangle have equal areas. The length of the rectangle is 12 inches, and its width is 8 inches. If the base of the triangle is 32 inches, what is the length, in inches, of the altitude drawn to the base?
the length of a rectangle is 8 more than the width. the area os 345 centimeters. find the length and width of the rectangle
A rectangle and a triangle have equal areas. The length of the rectangle is 12 inches, and its width is 8 inches. If the base of the triangle is 32 inches, what is the length, in inches, of the altitude drawn to the base? WRONG WRONG WRONG NO NO NO ::"::":""::":"""::"":":""::::::::::::: ::"::": ::":: :: ::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::"
Find the length of the hypotenuse of a right triangle whose legs are 8 and 15 units in length.
6
6
Perimeter = 2*(Width + Length) So 40 = 2*(8 + Length) 20 = 8 + Length Length = 12.
Easy. Width = 2ft, Length = 4 ft, therefore the Area = 8 ft.
6
If the length of a rectangle is twice its width and it has a perimeter of 48, then the rectangle is 16 in length and 8 in width.
6 inches