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To find the quadratic polynomial whose zeros are 2 and -3, we can use the fact that a polynomial can be expressed in factored form as ( f(x) = a(x - r_1)(x - r_2) ), where ( r_1 ) and ( r_2 ) are the zeros. Here, substituting ( r_1 = 2 ) and ( r_2 = -3 ), we have ( f(x) = a(x - 2)(x + 3) ). Expanding this, we get ( f(x) = a(x^2 + x - 6) ). For simplicity, we can choose ( a = 1 ), giving us the polynomial ( f(x) = x^2 + x - 6 ).
What else can I help you with?
7w squared minus 17w plus 16?
7w2 -17w+16 is a polynomial that cannot be factored. We call this a prime polynomial.There are also no like terms to combine. So nothing much more can be done with this polynomial. If you wanted to find the roots or the zeros, you could use the quadratic formula.
State whether the following is a polynomial function give the zero s of the function if the exist f x x 2-6x plus 8?
The function ( f(x) = x^2 - 6x + 8 ) is a polynomial function because it is a quadratic expression. To find the zeros, we can factor it as ( (x - 2)(x - 4) ), which gives us the zeros ( x = 2 ) and ( x = 4 ). Thus, the zeros of the function are 2 and 4.
In given figure graph of polynomial x is given find the zero of polynomial?
To find the zeros of the polynomial from the given graph, identify the points where the graph intersects the x-axis. These intersection points represent the values of x for which the polynomial equals zero. If the graph crosses the x-axis at specific points, those x-values are the zeros of the polynomial. If the graph merely touches the x-axis without crossing, those points indicate repeated zeros.
What are the zeros of the polynomial function f(x)x3-2x2-8x?
To find the zeros of the polynomial function ( f(x) = x^3 - 2x^2 - 8x ), we first factor the expression. We can factor out ( x ) from the polynomial, giving us ( f(x) = x(x^2 - 2x - 8) ). Next, we can factor the quadratic ( x^2 - 2x - 8 ) into ( (x - 4)(x + 2) ), leading to ( f(x) = x(x - 4)(x + 2) ). Therefore, the zeros of the function are ( x = 0 ), ( x = 4 ), and ( x = -2 ).
How do you find the zeros of cubic polynomial equation?
If the cubic polynomial you are given does not have an obvious factorization, then you must use synthetic division. I'm sure wikipedia can tell you all about that.
How do you find the zeros of any given polynomial function?
by synthetic division and quadratic equation
How do you find polynomial whose zeros are given?
when the equation is equal to zero. . .:)
How Find a polynomial degree of 3 whose zeros are -2 -1 and 5?
Multiply x3 - 2x2 - 13x - 10
How can you use a graph to find zeros of a quadratic function?
The zeros of a quadratic function, if they exist, are the values of the variable at which the graph crosses the horizontal axis.
What is the remainder thereom?
The remainder theorem states that if you divide a polynomial function by one of it's linier factors it's degree will be decreased by one. This theorem is often used to find the imaginary zeros of polynomial functions by reducing them to quadratics at which point they can be solved by using the quadratic formula.
7w squared minus 17w plus 16?
7w2 -17w+16 is a polynomial that cannot be factored. We call this a prime polynomial.There are also no like terms to combine. So nothing much more can be done with this polynomial. If you wanted to find the roots or the zeros, you could use the quadratic formula.
State whether the following is a polynomial function give the zero s of the function if the exist f x x 2-6x plus 8?
The function ( f(x) = x^2 - 6x + 8 ) is a polynomial function because it is a quadratic expression. To find the zeros, we can factor it as ( (x - 2)(x - 4) ), which gives us the zeros ( x = 2 ) and ( x = 4 ). Thus, the zeros of the function are 2 and 4.
In given figure graph of polynomial x is given find the zero of polynomial?
To find the zeros of the polynomial from the given graph, identify the points where the graph intersects the x-axis. These intersection points represent the values of x for which the polynomial equals zero. If the graph crosses the x-axis at specific points, those x-values are the zeros of the polynomial. If the graph merely touches the x-axis without crossing, those points indicate repeated zeros.
What are the zeros of the polynomial function f(x)x3-2x2-8x?
To find the zeros of the polynomial function ( f(x) = x^3 - 2x^2 - 8x ), we first factor the expression. We can factor out ( x ) from the polynomial, giving us ( f(x) = x(x^2 - 2x - 8) ). Next, we can factor the quadratic ( x^2 - 2x - 8 ) into ( (x - 4)(x + 2) ), leading to ( f(x) = x(x - 4)(x + 2) ). Therefore, the zeros of the function are ( x = 0 ), ( x = 4 ), and ( x = -2 ).
What statement must be true of an equation before you can use the quadratic formula to find the solutions?
The quadratic formula can be used to find the solutions of a quadratic equation - not a linear or cubic, or non-polynomial equation. The quadratic formula will always provide the solutions to a quadratic equation - whether the solutions are rational, real or complex numbers.
How do you find the zeros of cubic polynomial equation?
If the cubic polynomial you are given does not have an obvious factorization, then you must use synthetic division. I'm sure wikipedia can tell you all about that.
What factor of 6x2 plus x1 - 11 in zeros of polynomial function?
That doesn't factor neatly. Applying the quadratic formula, we find two real solutions: (-1 plus or minus the square root of 265) divided by 12 x = 1.2732350496749756 x = -1.439901716341642
