The unit digit of a two digit number exceeds twice the tens by one find the number is the sum of its digits is ten?

Answer 1

let x- unit digit

2x + 1- twice the tens by one

x + 2x +1 = 10

x + 2x = 10 - 9

3x= 9

x = 3

therefore : x = 3

2x + 1 = 7

the number is 37.

you can try checking it:

x + 2x + 1 = 10

3 + 2(3) = 10-1

3 + 6 = 9

9 = 9