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The unit digit of a two digit number exceeds twice the tens by one find the number is the sum of its digits is ten?
Wiki User
∙ 12y ago
let x- unit digit
2x + 1- twice the tens by one
x + 2x +1 = 10
x + 2x = 10 - 9
3x= 9
x = 3
therefore : x = 3
2x + 1 = 7
the number is 37.
you can try checking it:
x + 2x + 1 = 10
3 + 2(3) = 10-1
3 + 6 = 9
9 = 9
Wiki User
∙ 12y ago
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