What are polar coordinates of (√2, 1)? Solution: Here we need to convert from rectangular coordinates to polar coordinates: P = (x, y) = (r, θ) r = ± √(x^2 + y^2); tan θ = y/x or θ = arc tan (y/x) So we have: P = (√2, 1) r = ± √[(√2)^2 + 1^2] = ± √3 θ = arc tan (y/x) = arc tan (1/√2) = arc tan (√2/2) ≈ 35.3°, which is one possible value of the angle. (√2, 1) is in the Quadrant I. If θ = 35.3°, then the point is in the terminal ray, and so r = √3. Therefore polar coordinates are (√3, 35.3°). Another possible pair of polar coordinates of the same point is (-√3, 215.3°) (180° + 35.3° = 215.3°). Edit: Note the negative in the r value.
oh my goodness not even dr.sheldon cooper can answer that
(7, -2)
The coordinate plane in 2-dimensional space has one point which is the origin. This point is usually denoted by the letter O and has coordinates (0, 0). There are usually two mutually perpendicular axes - one horizontal and one vertical. The first coordinate of any point is the distance of the point, in the horizontal direction, from the vertical axis. The second is its distance, in the vertical direction, from the horizontal axis. In space with 3 or more dimensions the coordinates are defined in an analogous manner.
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The point whose Cartesian coordinates are (-3, -3) has the polar coordinates R = 3 sqrt(2), Θ = -0.75pi.
What are polar coordinates of (√2, 1)? Solution: Here we need to convert from rectangular coordinates to polar coordinates: P = (x, y) = (r, θ) r = ± √(x^2 + y^2); tan θ = y/x or θ = arc tan (y/x) So we have: P = (√2, 1) r = ± √[(√2)^2 + 1^2] = ± √3 θ = arc tan (y/x) = arc tan (1/√2) = arc tan (√2/2) ≈ 35.3°, which is one possible value of the angle. (√2, 1) is in the Quadrant I. If θ = 35.3°, then the point is in the terminal ray, and so r = √3. Therefore polar coordinates are (√3, 35.3°). Another possible pair of polar coordinates of the same point is (-√3, 215.3°) (180° + 35.3° = 215.3°). Edit: Note the negative in the r value.
Points: (-3, 2) and (7, 6) Slope: 2/5 Equation: 5y-2x = 16 x intercept: (-8, 0)
In 2-d: (0, y) In 3-d: (0, y, 0) In 4-d: (0, y, 0, 0) and so on.
(-2, 90) apex, but another "expert verified answer" from brainly suggests (2,0)
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The origin is located at the point whose coordinates are (0, 0) in 2-dimensional space or (0, 0, 0) in 3-dimensional space.
The midpoint formula is: [(x1 + x2)/2, (y1 + y2)/2]. If we denote the coordinates of the point C as (x1, y1) = (2, 6), and the coordinates of the point D as (x2, y2) = (4, 0), we can find the coordinates of the midpoint by using the above formula. So, [(x1 + x2)/2, (y1 + y2)/2] = [(2 + 4)/2, (6 + 0)/2] = (3, 3)
oh my goodness not even dr.sheldon cooper can answer that
Another way to classify a point is with the polar system. A polar coordinate, instead of (x, y), is (r, theta). To find r, you can use the Pythagorean Theorem, a^2 + b^2 = c^2.In this case, a = 2 and b = 4, or vice versa. That means that c, or r, equals 2 square roots of 5, or 2sqrt5.To find theta, you can use this formula: theta = tan inverse(y/x). With point (2,4), theta equals approximately 63.43 degrees, or 514394/8109This, as a polar coordinate, is (2sqrt5, (514394/8109))Using the polar system, however, you can express this point in infinitely many different ways. Just add/subtract 360 degrees to/from theta and you have the same point again.
(7, -2)
Coordinates are what tells you where a "point" is on a coordinate plane. For instance, Point A may be at (4, 6) when Point B is at (-2, 5)