16
31
The answer would be 10 12 and 14... 14 x 3 = 42 and 2(10 + 12) = 44. So the product of the largest integer and three is two less than twice the sum of the lower integers.
When the integers are negative.
Divide the sum of the three consecutive odd integers by 3: 159/3 = 53. The smallest of these integers will be two less than 53 and the largest will be two more than 53, so the three consecutive odd integers will be 51, 53, and 55.
1/2 and 1/2
22
14 and 6
31
The numbers are 11, 13, 15 and 17.
The product of four consecutive integers is always one less than a perfect square. The product of four consecutive integers starting with n will be one less than the square of n2 + 3n + 1
That happens when only one of the two integers is negative.
1, 2, 3, 4, and their negatives.
They are 6, 8, 10 and 12.
The integers are 5 and 7.
The positive integers whose squares are less than 30 are 1, 2, 3, 4, and 5. This is because the squares of these numbers are 1, 4, 9, 16, and 25, respectively, all of which are less than 30. The next integer, 6, has a square of 36, which exceeds 30.
81
The answer would be 10 12 and 14... 14 x 3 = 42 and 2(10 + 12) = 44. So the product of the largest integer and three is two less than twice the sum of the lower integers.