31
16
4 and 6 6 and 8 Any time the two numbers have a common factor, their LCM will be less than the product because the common factor contributes to the LCM fewer times than it contributes to the product.
The answer would be 10 12 and 14... 14 x 3 = 42 and 2(10 + 12) = 44. So the product of the largest integer and three is two less than twice the sum of the lower integers.
Divide the sum of the three consecutive odd integers by 3: 159/3 = 53. The smallest of these integers will be two less than 53 and the largest will be two more than 53, so the three consecutive odd integers will be 51, 53, and 55.
When the integers are negative.
22
16
14 and 6
The numbers are 11, 13, 15 and 17.
4 and 9 7 and 8
Pairs with common factors other than 1.
The product of four consecutive integers is always one less than a perfect square. The product of four consecutive integers starting with n will be one less than the square of n2 + 3n + 1
They are 6, 8, 10 and 12.
n(n+1) <10000 so n is close to square-root of 10000 which is 100. Obviously 100x101 is too much, but 99x100 is OK
4 and 6 6 and 8 Any time the two numbers have a common factor, their LCM will be less than the product because the common factor contributes to the LCM fewer times than it contributes to the product.
The integers are 5 and 7.
That happens when only one of the two integers is negative.