0
That can't be simplified. If you have a value for x, you can calculate the expression. Be sure to put your calculator into the correct mode; the angle can be measured either in radians or degrees. You have to know what measurement is being used, but if the angle is written as "x", radians are commonly used.
That can't be simplified. If you have a value for x, you can calculate the expression. Be sure to put your calculator into the correct mode; the angle can be measured either in radians or degrees. You have to know what measurement is being used, but if the angle is written as "x", radians are commonly used.
That can't be simplified. If you have a value for x, you can calculate the expression. Be sure to put your calculator into the correct mode; the angle can be measured either in radians or degrees. You have to know what measurement is being used, but if the angle is written as "x", radians are commonly used.
That can't be simplified. If you have a value for x, you can calculate the expression. Be sure to put your calculator into the correct mode; the angle can be measured either in radians or degrees. You have to know what measurement is being used, but if the angle is written as "x", radians are commonly used.
That can't be simplified. If you have a value for x, you can calculate the expression. Be sure to put your calculator into the correct mode; the angle can be measured either in radians or degrees. You have to know what measurement is being used, but if the angle is written as "x", radians are commonly used.
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How do you integrate open bracket x plus 1 close bracket cosx?
Try integration by parts, (twice, I think) with u=(x+1) and dv/dx=cosx
Sinx plus cosx equals 0?
x = 3pi/4
What are the solutions of 2 cos squared x minus cos x equals 1?
2cos2x - cosx -1 = 0 Factor: (2cosx + 1)(cosx - 1) = 0 cosx = {-.5, 1} x = {...0, 120, 240, 360,...} degrees
How do you prove the following identity sec x - cos x equals sin x tan x?
you need this identities to solve the problem..that is something you have to memorized sec x= 1/cosx 1-cos2x= sin2x tanx= sin x/cosx also, sin 2x= (sinx)(sinx) sec x - cosx= sin x tanx (1/cosx)-cosx= sin x tanx .. 1-cos2x / cosx=sin x tanx sin2x/ cosx= sin x tanx (sin x/cox)( sin x)= sin x tanx tanx sinx= sin x tanx
What is secx?
secx is the inverse of cosx. secx=1/cosx. A secant is also a line drawn through the graph that touches two points on a function.
Prove this identity 1 plus cosx divide by sinx equals sinx divide by 1-cosx?
2
What is the differentiation of sin x over 1 plus cosx?
The derivative is 1/(1 + cosx)
How do you solve 1 minus cosx divided by sinx plus sinx divided by 1 minus cosx to get 2cscx?
(1-cosx)/sinx + sinx/(1- cosx) = [(1 - cosx)*(1 - cosx) + sinx*sinx]/[sinx*(1-cosx)] = [1 - 2cosx + cos2x + sin2x]/[sinx*(1-cosx)] = [2 - 2cosx]/[sinx*(1-cosx)] = [2*(1-cosx)]/[sinx*(1-cosx)] = 2/sinx = 2cosecx
How does secx plus 1 divided by cotx equal 1 plus sinx divided by cosx?
secx = 1/cosxand 1/cotx = tanx, therefore1/cosx + tanx = 1 + sinx/cosx, andsin/cos = tanx, therefore1/cosx + tanx = 1 + tanx, therefore1/cosx = 1, therfore1 = cosx.So, therfore, it is not neccesarily true.But if you meansecx plus 1 divided by cotx equals (1 plus sinx) divided by cosx(this is probably what you mean) Let's start over!secx = 1/cosxand 1/cotx = tanx, therefore1/cosx + tanx = (1+sinx)/cosx therefore1/cosx + tanx = 1/cosx + sinx/cosxsinx/cosx = tanx therfore1/cosx + tanx = 1/cosx + tanxDo you think this is correct? Subtract both sides by 1/cosx + tanx:0 = 0So, therefore, this is correct!(BTW, I'm in Grade 6! :P)
What is 1 minus cosx divided by since minus since divided by 1 plus cosx?
2
How do you simplify cosx plus sinx tanx?
to simplify Cosx=Sinx Tanx you should remember your fundamental and pythagorean identities.. Cosx + Sinx Tanx Cosx + Sinx (Sinx/Cosx) <---------- From Tanx= Sinx/Cosx Cosx + Sin2x/ Cos x <------------- do the LCD Cosx (Cosx/Cosx) + Sin2x/Cosx (Cos2x+Sin2x)/Cosx 1/Cosx <--------- From Sin2x + Cos2x =1 or Secx <-------- answer Comment if you have questions...:))
Differentiation of sin x 1 plus cosx?
The differentiation of sin x plus cosx is cos (x)-sin(x).
What is the derivative of 1 plus cosx?
negative sin(x)
What is (1 plus cos x)(1- cos x)?
(1+cosx)(1-cosx)= 1 +cosx - cosx -cos^2x (where ^2 means squared) = 1-cos^2x = sin^2x (sin squared x)
How do you prove the following equation the quantity of sin theta divided by 1 minus cos theta minus the quantity 1 plus cos theta divided by sin theta equals 0?
You will have to bear with the angle being represented by x because this browser will not allow characters from other alphabets!sin^2x + cos^2x = 1=> sin^2x = 1 - cos^x = (1 + cosx)(1 - cosx)Divide both sides by sinx (assuming that sinx is not zero).=> sinx = (1 + cosx)(1 - cosx)/sinxDivide both sides by (1 - cosx)=> sinx/(1 - cosx) = (1 + cosx)/sinx=> sinx/(1 - cosx) - (1 + cosx)/sinx = 0
How do you solve sin squared x divided by 1 - cos x?
Use this identity sin2x+cos2x=1 sin2x=1-cos2x so sin2x/(1-cosx) =(1-cos2x)/(1-cosx) =(1-cosx)(1+cosx)/(1-cosx) =1+cosx
How do you simplify tanx plus tany per cosx plus coty?
(tan x- 1)/ (1+tan x)
