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That's the reason I some what dis like High School Math ---- it leaves to many blanks.

When the book writes y = something about x. It is describing a function, some times just a relation, but relations are not as fun.

The proper way to do it, let f be a real map (function) from the real numbers to the real numbers (which I assume you are working on the real numbers), denote f:R ---> R

R stands for real.

Then we let y = f(x) for all x. That's what is going on. y is the out come, or the result of the function performed on x. In this case, we multiply x by an arbitrary k. And that's all there is. It means, y is the result of a function on x that involves multiplying x by a factor k.

Ah hah! We say, one formal definition of a function is its graph, the set of all pairs (x, y) where y = f(x). Are they related here? Yes. It is very important (it's the definition) to link them. What the graph looks like is a straight that is tilted in various degree, 0 degree included to 90 degree excluded. As to WHY it look like that, there is a tool called Calculus, which require some proof to figure. If you want to know, ask or message me.

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Q: What does y equals kx mean?
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Find a equation of variation where y varies directly as x and y equals 0.8 when x equals 0.4?

direct variation: y = kx y = kx k = y/x = 0.8/0.4 = 2


A type of variation in the form y equals kx?

Y varies in direct proportion to x.


If y varies directly as x squared and y equals 150 when x equals 5 find y when x equals 4?

First you need to know that the equation you are looking for is y = kx^2. Then you need to substitute the numbers in: y = kx^2 150 = k5^2 150 = k25 6 = k Now that you know k, resubstitute it for the new value of y when x = 4: y = kx^2 y = (6)(4)^2 y = (6)(16) y = 96


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There are no "following" data!


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y = kx k = y/x = 21/-5 = - 21/5


What is the value of k in the line of y equals kx plus 1 and is tangent to the curve of y squared equals 8x?

If: y = kx+1 is a tangent to the curve y^2 = 8x Then k must equal 2 for the discriminant to equal zero when the given equations are merged together to equal zero.


What if y equals kx?

You then have a linear relationship, or a direct variation. A straight line through the origin.


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What are the values of k when the line kx plus y equals 4 touches the curve y equals x squared plus 8 on the Cartesian plane showing work?

If: y = x^2 +8 and kx +y = 4 or y = 4 -kx Then: x^2 +8 = 4 -kx So: x^2 +8 -4 +kx = 0 => x^2 +4 +kx = 0 Using the discriminant b^2 -4ac = 0: k^2 -4*1*4 = 0 => k^2 = 16 Therefore the values of k are: -4 or 4 Hence: y-4x = 4 and y+4x = 4 are tangents to the curve y = x^2 +8


What is the value of k when the line y equals kx plus 1.25 is a tangent to the curve y squared equals 10x?

Equations: y = kx +1.25 and y^2 = 10x If: y = kx +1.25 then y^2 = (kx +1.25)^2 =>(kx)^2 +2.5kx +1.5625 So: (kx)^2 +2.5kx +1.5625 = 10x Transposing terms: (kx)^2 +2.5kx +1.5625 -10x = 0 Using the discriminant formula: (2.5k -10)^2 -4(1.5625*k^2) Multiplying out the brackets: 6.25k^2 -50k +100 -6.25^2 = 0 Collecting like terms: -50k +100 = 0 Solving the above equation: k = 2 Therefore the value of k is: 2


If y Varies Directly as x to the 2nd power and y equals 198 when x equals 6 find y when x equals 2?

y=kx^2 hence k=198/36. now y=198/36*(2)^2 y=22


If y varies directly as x and y equals 18 when x equals 3?

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