The definite integral of any function identically equal to zero between any two points is zero.
Integral is the area under the graph of the given function. Sometimes the terms "integral" or "indefinite integral" are used to refer to the general antiderivative of a function, especially in many textbooks. In this case, the indefinite integral is equal to an arbitrary constant, and it is important to distinguish between these two cases.
The Integral diverges. It has singularities whenever sin(x)+cos(x)=0. Singularities do not necessarily imply that the integral goes to infinity, but that is the case here, since the indefinite integral is x/2 + 1/2 Log[-Cos[x] - Sin[x]]. Obviously this diverges when evaluated at zero and 2pi.
In order to evaluate a definite integral first find the indefinite integral. Then subtract the integral evaluated at the bottom number (usually the left endpoint) from the integral evaluated at the top number (usually the right endpoint). For example, if I wanted the integral of x from 1 to 2 (written with 1 on the bottom and 2 on the top) I would first evaluate the integral: the integral of x is (x^2)/2 Then I would subtract the integral evaluated at 1 from the integral evaluated at 2: (2^2)/2-(1^2)/2 = 2-1/2 =3/2.
integral (a^x) dx = (a^x) / ln(a)
Integral of [1/(sin x cos x) dx] (substitute sin2 x + cos2 x for 1)= Integral of [(sin2 x + cos2 x)/(sin x cos x) dx]= Integral of [sin2 x/(sin x cos x) dx] + Integral of [cos2 x/(sin x cos x) dx]= Integral of (sin x/cos x dx) + Integral of (cos x/sin x dx)= Integral of tan x dx + Integral of cot x dx= ln |sec x| + ln |sin x| + C
The antiderivative, or indefinite integral, of ex, is ex + C.
the cyclic integral of this is zero
An integral number is an integer. A whole number positive, negative or zero.
Same as any other function - but in the case of a definite integral, you can take advantage of the periodicity. For example, assuming that a certain function has a period of pi, and the value of the definite integral from zero to pi is 2, then the integral from zero to 2 x pi is 4.
The integral zeros of a function are integers for which the value of the function is zero, or where the graph of the function crosses the horizontal axis.
The electric flux depends on charge, when the charge is zero the flux is zero. The electric field depends also on the charge. Thus when the electric flux is zero , the electric field is also zero for the same reason, zero charge. Phi= integral E.dA= integral zcDdA = zcQ Phi is zcQ and depends on charge Q, as does E.
non integral is type of numbers behaviour: i can say that set of numbers without any "holes inside" are integral and set of numbers with "holes inside are non integral. example : integral group "1..100" non integral group "1,4,8,67"
The integral zeros of a function are integers for which the value of the function is zero, or where the graph of the function crosses the horizontal axis.
It depends on the maximum value of c. In signed values, the maximum value we can store in an integral is 2 to the power of the number of bits in the integral, minus 1. Thus a 32-bit signed integral can accommodate all positive values in the range 2^31, which is 2,147,483,648.
The Integral diverges. It has singularities whenever sin(x)+cos(x)=0. Singularities do not necessarily imply that the integral goes to infinity, but that is the case here, since the indefinite integral is x/2 + 1/2 Log[-Cos[x] - Sin[x]]. Obviously this diverges when evaluated at zero and 2pi.
It is unclear what you mean. If you mean that you want to find momentum but do not have a value for velocity then it depends on what physical system you are using. If you want to find the momentum of an object with a velocity equal to zero then the momentum is zero. Answer2. You can find the momentum from its the integral of its force impulse fdt = d(mv). The momentum is mv= integral of fdt.
Yes, the integral heat of solution can be zero when there is no heat absorbed or released during the dissolution of a solute in a solvent. This can happen when the enthalpy change of the solution process is exactly balanced by the energy required to disrupt the solvent-solute interactions.
For the integral to equal 2012, we need the derivative of 2012. Because this is zero, we could assume that there are no values that would give you 2012. However, if you integrate 0, you get a constant, and therefore, because we can choose this constant to be whatever we require, the integral of 0 could possibly equal 2012. However, if you are (more likely) required to find the integral of 2012, its 2012x, or the derivative of 2012 is as mentioned earlier, 0