9 3 1
each time the number increases by 8 and the original number was 3.This means that nth term = 3+(n-1)8ie. the fourth term 27 would be 3 + (4-1)x8 = 3+24 = 27
yes it can 27 times Cuz 81 divided by 3 is 27
81
The given sequence is an arithmetic sequence with a common difference that increases by 1 with each term. To find the nth term of an arithmetic sequence, you can use the formula: nth term = a + (n-1)d, where a is the first term, n is the term number, and d is the common difference. In this case, the first term (a) is 3 and the common difference (d) is increasing by 1, so the nth term would be 3 + (n-1)(n-1) = n^2 + 2.
9 3 1
tn = 3n or 3*3* ... *3 (where there are n threes.)
81
The first four terms are 3 9 27 81 and 729 is the 6th term.
For each term, multiply the previous by -3. So, 27*-3=-81. -81 is the next term.
There is no pattern
each time the number increases by 8 and the original number was 3.This means that nth term = 3+(n-1)8ie. the fourth term 27 would be 3 + (4-1)x8 = 3+24 = 27
The nth term is: 5-2n
yes it can 27 times Cuz 81 divided by 3 is 27
81
after -9 it is -15 then -21, -27 and the ninth is -36
Nth term With the nth term you substitute the n for the term number (e.g. 50) so the 50th term in 2n+3 would be 2x50+3=103