each time the number increases by 8 and the original number was 3.
This means that nth term = 3+(n-1)8
ie. the fourth term 27 would be 3 + (4-1)x8 = 3+24 = 27
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Well, darling, the nth term of this sequence is n^2 + 2. So, if you plug in n=1, you get 3, n=2 gives you 11, n=3 spits out 19, and n=4 pops up with 27. Simple as that, sugar.
The nth term of the sequence is (n + 1)2 + 2.
2n +29
It is: 27-2n
The given sequence is an arithmetic sequence with a common difference that increases by 1 with each term. To find the nth term of an arithmetic sequence, you can use the formula: nth term = a + (n-1)d, where a is the first term, n is the term number, and d is the common difference. In this case, the first term (a) is 3 and the common difference (d) is increasing by 1, so the nth term would be 3 + (n-1)(n-1) = n^2 + 2.
5n+2