[ 9x2 - 10x + 1 ] is not a question. If you were to turn it into a statement, by
setting it equal to something, then you could ask us what number 'x' must be
in order to make the statement true. But right now, it's only an expression
that stands for some number, and in order to know what number, we'd first
need to know what number 'x' is.
You can calculate a value if you assign a value to variable "x".
(2x - 1)(5x + 8)
You don't need to factor that; you can add them together, since they have the same variable.However, assuming you might mean 81x squared + 9x, you can take out the common factor, which is 9x.
(x + 2)(3x - 1)(3x + 1)
104
x - 10x = 9x, so 9x + 3 = 0, so 9x = -3 so x = -1/3
9x2 + 8x - 1 = (9x - 1)(x + 1)
-10x+3 = -x+12 -10x+x = 12-3 -9x = 9 x = -1
3x2 + 10x + 3 = (x + 3)(3x + 1).
3(x2 + 3x + 1)
(x+1)(x+8)
Do a bit of rearrangement: 1: 10x + 2 = 8y; 2: 8y = 59 - 9x so 10x + 2 = 59 - 9x so 19x - 57 making x = 3 and y is therefore 4.
x2 - 9x + 8 = (x-1)(x-8)
2x2-9x+4 = (2x-1)(x-4) when factored
You can calculate a value if you assign a value to variable "x".
x2-9x+8=0 has two solutions:x = 8x = 1
since y = 3x+1 we have y squared =(3x+1) squared x^2 + y^2 = 25 x^2 + (3x+1)^2=25 x^2 + 9x^2+ 6x+1 = 25 10x^2 + 6x + 1 = 25 10x^2 + 6x -24 = 0 solve x from quadratic formula x = 1.28 y = 3x + 1 = 4.83