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What is the answer to this problem cos 5x plus 49 sin 3x plus 57?
ElreaseHarrisgp3055
There are operators missing.
The only question that I can see to make sense is:
Solve x for: cos(5x + 49°) = sin(3x + 57°)
It's been a while since I did this kind of problem, so there may be more solutions to the ones I give here:
Cosθ = sin(90 - θ)
→ cos(5x + 49°) = sin(3x + 57°)
→ sin(90° - (5x + 49°)) = sin(3x + 57°)
→ sin(41° - 5x) = sin(3x + 57°)
Thus:
41° - 5x = 3x + 57°
→ 8x = -16°
→ x = -2°
But as sin and cos are cyclic with a period of 360°, -2° = 360° - 2= 358°
→ x = 358° + 360°n where n = 0, 1, 2, ....
But sin θ = sin(180° - θ) which means that
180 - (41° - 5x) = 3x + 57°
→ 5x + 139° = 3x + 57°
→ 2x = -82°
→ x = -41°
→ x = 319° + 360°n where n = 0, 1, 2, 3,... is also a solution set.
Thus the solutions are:
x = 358° + 360°n
x = 319° + 360°n
where n = 0, 1, 2, 3, ...
Wiki User
∙ 7y ago
Wiki User
∙ 7y agoThere is no answer because there is no equation to be solved. The value of the expression will depend on the variable x and will lie in the range [8, 106].
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