Area = 10 sq cm
If the quadrilateral is a square then all of its sides are the same length. ac is not one of the sides but is a diagonal which forms the hypotenuse of a right angle triangle with sides ab and bc. According to Pythagoras the sum of the square of the hypotenuse is equal to the sum of the squares of the other two sides. As side ab measures 10 then 10 squared = 100. Side bc has the same measurements. The square of side ac must equal 200 (100 + 100) so the length of side ac must equal the square root of 200 (100 + 100) which is 14.14 (to 2 decimal places).
Find ab
(ab) raised to 1/2 power
AB can be found by using the distance formula, which is the square root of (x2-x1)^2 + (y2-y1)^2. In this case, AB= the square root of (-2-(-8))^2 + (-4-(-4))^2 which AB= the square root of 64 + 0 which AB=8.
The length of its side squared.
Lateral area: Twice the side of the square times the slant height. Surface area: The side of the square squared plus twice the side of the square times the slant height. a=side of square b=slant height L.A.=2(ab) S.A.=(a)(a)+(2(ab))
7 inches
12
Not too sure about the question as there is no triangle pictured at the right. But in general the area of a triangle is 0.5*base*perpendicular height
Octagon is composed of 8 triangles, which can be combined in pairs to make 8 rectangles of which one side is the apothem. The area is 1.657 x the square of the apothem, simplified from 4 times the square of the apothem divided by tan67.5o ie 2.4142. 4 divided by 2.4142 is 1.657. Consider triangle OAB where OB is the apothem and AB is half of a side: The angle OAB = 67.5 degrees, half of the interior angle of a regular hexagon. Tan 67.5 = OB/AB so AB = OB/tan 67.5 and the area of each notional rectangle is OB squared divided by tan 67.5. There are four such rectangles hence 4OB2/tan 67.5 is the area of the octagon.
If you have two straight lines AB and BC such that the two lines meet at B and AB and BC make 90 degrees with each other then the pythagorean theory (theoram) states that the length of line AC (assume that points A and C are joined by a straight line) then (AC) squared = (AB) squared +(BC) squared
Area = 10 sq cm
By using Pythagoras' theorem for a right angle triangle if side AB is the hypotenuse it is the square root of 149 which is about 12.207 rounded to three decimal places
If the octagon at the base is regular, the side of the octagon is s and the height of the prism is h, the area of each octagonal base (Ab) is Ab = 2(√2 +1) s2 The perimeter of the octagon is P = 8s Then the surface area of the prism is As = 2 Ab + Ph The volume of the prism is V = Ab h
it couldn't be a rectangle it would be a square and it would =24
If the quadrilateral is a square then all of its sides are the same length. ac is not one of the sides but is a diagonal which forms the hypotenuse of a right angle triangle with sides ab and bc. According to Pythagoras the sum of the square of the hypotenuse is equal to the sum of the squares of the other two sides. As side ab measures 10 then 10 squared = 100. Side bc has the same measurements. The square of side ac must equal 200 (100 + 100) so the length of side ac must equal the square root of 200 (100 + 100) which is 14.14 (to 2 decimal places).