Equation of a circle with centre (x0, y0) and radius r is (x - x0)^2 + (y - y0)^2 = r^2
→ circle is:
(x - -2)^2 + (y - 3)^2 = 5^2
→ (x + 2)^2 + (y - 3)^2 = 5^2
→ x^2 + 4x + 4 + y^2 - 6y + 9 = 25
→ x^2 + 4x + y^2 - 6y - 12 = 0
The equation of a circle can be written in the form (x-h)2 + (y - k)2 = r2, where r is the radius, and (h,k) is the center. So for your example, the equation would be: (x- 5)2 + (y - 3)2 = 72
If you mean: (x+9)^2 + (y+5)^2 = 64 Then the center of the circle is at (-9,-5) and the radius is 8
x2+y2+4x+2y+3=0(x+2)2 + (Y+2.5)2 = 3This is the equation of circle with center at (-2,-2.5) with radius 3.5
(x + 4)2 + (y + 3)2 = 49 is.
There are probably several ways to approach it; one general equation for the circle is: (x - a)2 + (y - b)2 = r2 This describes a circle with center at coordinates (a, b), and with a radius of r.
Equation of any circle, with any radius, and its center at any point: [ x - (x-coordinate of the center) ]2 + [ y - (y-coordinate of the center) ]2 = (radius of the circle)2
The standard equation of a circle, with center in (a,b) and radius r, is: (x-a)2 + (y-b)2 = r2
The equation of circle is (x−h)^2+(y−k)^2 = r^2, where h,k is the center of circle and r is the radius of circle. so, according to question center is origin and radius is 10, therefore, equation of circle is x^2 + y^2 = 100
depends on the equation.
Center of circle: (6, 8) Radius of circle: 3
The equation of the circle is: x^2 + y^2 = 81
Centre of the circle: (3, 8) Radius of the circle: 2 Cartesian equation of the circle: (x-3)^2 + (y-8)^2 = 4
Equation of circle: (x-2)^2 +(y+9)^2 = 49
If you mean a circle center at (3, 1) and a radius of 2 then the equation of the circle is (x-3)^2 +(y-1)^2 = 4
The equation of the circle is: (x+3.2)^2 +(y+2.1)^2 = 18.49
center 5,-3 radius 4
x² + y² = 4.