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P = 2(L + W)
50 = 2(L + W)
25 = L + W
Let L = x, so W = 25 - x
A = LW
A = x(25 - x)
A = -x2 + 25x
Since the parabola that represents the above equation opens downward, we have a maximum point (the y-coordinate value of the vertex of the parabola, gives us the maximum value of the area).
vertex x-coordinate value = - b/2a = - 25/-2 = 25/2
vertex y-coordinate value = -(25/2)2 + 25(25/2) = - 252/4 + 252/2 = - 252/4 + 2(252)/4 = 252/4 = 156.25
Thu, the maximum area will be 156.25 unit2.
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What is the perimeter of 50 yards and 100 yards?
The perimeter of a rectangle of dimensions 50 yards x 100 yards is 300 yards.
Find the perimeter of a rectangle with the length of 15and the width of 10?
The formula to calculate perimeter of a rectangle is P=2L+2W P= 2(15) + 2(10) P= 30 +20 P = 50
The length of a rectangle is twice its width If the area of the rectangle is less than 50 square meters what is the greatest width of the rectangle?
From the statement of the problem, if w is the width, the area is 2w2 , the product of the width and the length, which is stated to be twice the width. Since 2w2 must be less than 50, w2 < 25, and the width must be less than 5 meters.
The length of a rectangle is twice its width If the area of the rectangle is 50yds2 What is the perimeter?
Answer: 30 yards. Explanation: let's say it is L yards long and W yards wide. Then perimeter is 2L+2W The area is LxW=50 So Since LW=50, we substitute L=2W and write 2W(W)=2W^2=50. so W^2=50/2=25 and W=5 Now 2W=10 which is L So is it 10 yards long and 5 yards wide Let's check that. Area is 10x5=50 as desired and Length is 10 which is twice 5 as desired Now perimeter is 2L+2W=2(10)+2(5)=20+10=30 yards.
The perimeter of a rectangle is 130m. The length of the rectangle is 25m more than the width. What are the lengths and widths of the rectangle?
x=width x+25=length 4x+50=130 4x=80 x=20 width is 20 length is 45
A factor pair for a rectangle with an area of 100 and a perimeter of 50?
(20,5)
Shapes with the same area do they have the same perimeter?
No.Rectangle 5 x 10. Area = 50. Perimeter = 30.Rectangle 2 x 25. Area = 50. Perimeter = 54.
What is the area of a rectangle that has a perimeter of 30 cm and the length is twice the width?
50 cm2
What are the dimensions of a rectangle that has a perimeter of 102 and an area of 50?
50' in Length by 1' in Width...50 x 1 = 50 :: 50+50+1+1=102
How many feet are in the perimeter of 50 acre?
You can't tell the perimeter from the area.If the 50-acre area has straight sides, then the shortest possible perimeter is5,903.2 feet, or about 1.118 miles. But it can be anydistance more than that.For example . . .-- If the plot is a rectangle 1,000-ft wide by 2,178-ft long, then its area is 50 acres,and its perimeter is 8,356-ft, or about 1.583 miles.-- If the plot is a rectangle 500-ft wide by 4,356-ft long, then its area is still 50 acres,but its perimeter is 9,712-ft, or about 1.84 miles.
How do you show the circumference of a rectangle with an area of 24?
I thought circumference is only with circles Absolutely correct, but even if you consider the perimeter, which is conceptually similar, there is no answer. A rectangle with an area of 24 could be 4*6 with a perimeter of 20 or it could be 1*24 with a perimeter of 50 or 0.5*48 with a perimeter of 97 etc
If a rectangle has an area of 2000 feet squared one side is fifty feet long what is the perimeter of the rectangle?
The formula for the area (A) of a rectangle is A = length x width : Let w be the unknown side then 2000 = 50w : w = 2000 ÷ 50 = 40 feet Perimeter of a rectangle = 2(length + width) = 2(50 + 40) = 2 x 90 = 180 feet
What is the perimeter of a rectangle with 50 feet as the length and 4 feet as the width?
108 feet is the perimeter of a rectangle with a length of 50 feet and a width of 4 feet.
What is the dimension of a rectangle with area 50 inches?
A few options (would help if given the perimeter) but they are 1x50/ 2x25/ 5x10
A rectangle had an area of 24ft2 what is the length and width of the rectangle with the greatest perimeter?
The rectangle with the smallest perimeter for a given area is the square. The rectangle with the greatestperimeter for a given area can't be specified. The longer and skinnier you make the rectangle, the greater its perimeter will become. No matter how great a perimeter you use to enclose 24 ft2, I can always specify a longer perimeter. Let me point you in that direction with a few examples: 6 ft x 4 ft = 24 ft2, perimeter = 20 ft 8 ft x 3 ft = 24 ft2, perimeter = 22 ft 12 ft x 2 ft = 24 ft2, perimeter = 28 ft 24 ft x 1 ft = 24 ft2, perimeter = 50 ft 48 ft x 6 inches = 24 ft2, perimeter = 97 ft 96 ft x 3 inches = 24 ft2, perimeter = 192.5 ft 288 ft x 1 inch = 24 ft2, perimeter = 576ft 2inches No matter how great a perimeter you find to enclose 24 ft2, I can always specify a rectangle with the same area and a longer perimeter.
A rectangle has a width of 12.4 ft and a length of 50 ftwhat is the length of the rectangle?
To answer the question as written: If the length of a rectangle is given as being 50 feet, then the length of the rectangle is 50 feet. To answer the question that is really being asked, if the width of a rectangle is 12.4 feet and the length of 50 feet, the area can be found by multiplying the length by the width. Therefore, the are of the rectangle would be 620 square feet. If however, the question was to determine the perimeter, you would use the formula 2l+2w=p so you would add 12.4 +12.4+50+50, for a perimeter of 124.8 feet.
What is the perimeter of 12 feet by 13 feet?
If that's a rectangle or a kite, then the perimeter is 50 feet.
