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a = b + 7; 2a = b2 - 1. Substituting: 2b + 14 = b2 - 1 or b2 - 2b - 15 = 0

Factors are (x - 5)(x + 3)

b = 5, a = 12. Also works with b = -3 and a = 4

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Q: What is the integers that have seven more than another integer Twice the larger integer is one less than the square of the smaller integer find the 2 integer?
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