The smallest number (greater than 9) that when divided by 9 would leave a remainder of 3 is 12. The next would be 21 and the next 30. Notice the pattern here, how each number (12, 21, 30) is 9 apart (since we are dividing each by 9).
For 12, the smallest is 15 followed by 27, then 39 and so on.
For 21: 24, 45, 66...
So we list them until we have one that is on all 3 lists:
9: 12, 21, 30, 39, 48, 57, 66, 75, 84, 93, 102, 111, 120, 129, 138, 147, 156, 165, 174, 183, 192, 201, 210, 219, 228, 237, 246, 255, 264, 273, 282, 291
12: 15, 27, 39, 51, 63, 75, 87, 99, 111, 123, 135, 147, 159, 171, 183, 195, 207, 219, 231, 243, 255, 267, 279, 291
21: 24, 45, 66, 87, 108, 129, 150, 171, 192, 213, 234, 255, 276, 297
The first number on all three lists is 255, so this is the smallest number into which 9, 12, and 21 can go into and in each case leave a remainder of 3.
Any number greater than 199 will divide into both zero times and leave a remainder (of the original number); there is no upper limit to the numbers greater than 199. -------------------------------- The largest number to divide into both and leave the SAME remainder is 56 (leaving a remainder of 31 in both cases).
No, 85 is not an even number. Even numbers are integers that are exactly divisible by 2, meaning they leave no remainder when divided by 2. In the case of 85, when divided by 2, it leaves a remainder of 1, making it an odd number.
76.5714
360
The least common multiple of 9, 36, and 60 is the smallest number that can be divided by each of the three numbers without a remainder. In this case, the answer is 180. (180/60 = 3, 180/36 = 5, and 180/9 = 20)
Any number greater than 199 will divide into both zero times and leave a remainder (of the original number); there is no upper limit to the numbers greater than 199. -------------------------------- The largest number to divide into both and leave the SAME remainder is 56 (leaving a remainder of 31 in both cases).
121
There is no such number. You can have arbitrarily large numbers with this property - therefore there is no largest.
The divisor of a number is a number which divides into that number. The least divisor of any number 1, so the least common divisor of 10 and 45 is also 1. Perhaps you meant "Least Common Multiple" (the smallest positive number which 10 and 45 divide without remainder) in which case LCM(10, 45) = 90 Or you meant "Highest Common Factor" (the largest positive number which divides into both 10 and 45 without remainder) in which case HCF(10, 45) = 5.
The number is 25.
No. When you divide a number by another number, let's say 26/4, you can't always get a perfect number. In this case, 6*4 is 24, and you have 2 "remainder", or 2 left over. The quotient is the whole answer, in this case 6 remainder 2. So the remainder is part of the quotient, but not the whole quotient itself.
No, 85 is not an even number. Even numbers are integers that are exactly divisible by 2, meaning they leave no remainder when divided by 2. In the case of 85, when divided by 2, it leaves a remainder of 1, making it an odd number.
To find the least number divisible by 23456 with a remainder of 1, you need to find the least common multiple (LCM) of 23456 and the number 1 more than it. The LCM of two numbers is the smallest number that is a multiple of both numbers. In this case, you would calculate the LCM of 23456 and 23457. The LCM can be found by multiplying the two numbers and then dividing by their greatest common divisor.
72.
The smallest number that can be subtracted from 1294, yielding a result that when divided by 9, 11, and 13 leaves a remainder of 6 is 1. To prove this, run the following snippit of a program int i; for (i=1294; i!= 0; i--) if (i % 9 6) break; printf("%u", 1294-i); another way to prove it it to multiply 9 11 and 13, yielding 1287, adding six, yielding 1293, which is one away from 1294.
742/105 = 7 remainder 7 1162/105 = 11 remainder 7
First, the word is remainder, not reminder.In any case, none of the followed numbers would give a remainder of 2 since there are no such numbers!First, the word is remainder, not reminder.In any case, none of the followed numbers would give a remainder of 2 since there are no such numbers!First, the word is remainder, not reminder.In any case, none of the followed numbers would give a remainder of 2 since there are no such numbers!First, the word is remainder, not reminder.In any case, none of the followed numbers would give a remainder of 2 since there are no such numbers!