If you mean: n2+16n+64 then it is (n+8)(n+8) when factored
16n
the answer is 4
(16n^8)^3/2
One possible solution is t(n)= [-4n3 + 21n2 - 16n + 18]/3
16n
If you mean: n2+16n+64 then it is (n+8)(n+8) when factored
Look at the coefficients. -16 - 14 = -30. Therefore, -16n - 14n = -30n.
The square root of 16n to the power of two, (√16n)2 is just simply 16n. Any number or monomial that is squared after the square root is taken is just the number itself, since squaring is the inverse property of taking the square root of something.
16n
6n2 + 16n can be factorised to give 2n(3n + 8) so the highest factor is 2n.
It is: 16n
(n - 4)(n - 12)
37 Fit the cubic: Un = (2n3 - 9n2 + 16n + 6)/3 for n = 1, 2, 3, ...
16O
As an algebraic term: 16n
2n(3n + 8)