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an^3 bn^2+cn+d=E(n) where E(n) is the value of the nth term and a,b, c and d are constants. So we have:
a+b+c+d=1
8a+4b+2c+d=0
27a+9b+3c+d=3
64a+16b+4c+d=8
Then work it out from there.
Assuming the first term was supposed to be -1 (minus 1) not 1 (plus one), then the nth term is given by:
tn = n2 - 2n
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