Oh, what a lovely sequence of numbers you have there! To find the pattern and the nth term, we can see that each number is increasing by adding consecutive even numbers (2, 4, 6, ...). So, the nth term can be found using the formula n^2 + 9. Keep exploring and creating, my friend!
f(n) = 14 - 6n -6n+20
[ 6n + 8 ] is.
The nth term is: 3n+2 and so the next number will be 20
t(n) = 10 - 6n where n = 1, 2, 3, ...
20 - (3 * (n - 1))
f(n) = 14 - 6n -6n+20
560
They are: nth term = 6n-4 and the 14th term is 80
[ 6n + 8 ] is.
It is: 26-6n
The nth term is: 3n+2 and so the next number will be 20
t(n) = 10 - 6n where n = 1, 2, 3, ...
20 - (3 * (n - 1))
The sequence 5, 10, 20, 40, 80 can be identified as a geometric progression where each term is multiplied by 2. The nth term can be expressed as ( a_n = 5 \times 2^{(n-1)} ), where ( a_n ) is the nth term. Thus, for any integer ( n ), you can find the term by substituting ( n ) into this formula. For example, the 1st term is 5, the 2nd term is 10, and so on.
a (sub n) = 11 + (n - 1) x d
The nth term is: 5n
The nth term of the sequence is expressed by the formula 8n - 4.