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ans=102 HOW? 6,11,13,27,38,.... 6(+5),11(+7),13(+9),27(+11),38(+13),51(+15),66(+17),83(+19),102adding 5 to 6 gives 11 adding 7(two greater than previous one) gives 13...and so on... to find the nth term N squared +2

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Wiki User

āˆ™ 15y ago
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Anonymous

Lvl 1
āˆ™ 4y ago
I get what you say.. Umn but..Ā  I mentally solved it..Ā  (n+1)^2+2 ... I really don't know how. But it worked šŸ¤£šŸ¤£
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It's Me Legend

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āˆ™ 2y ago
It is tn=nĀ²+2n+3
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Mozon omar

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āˆ™ 2y ago
which term in the sequence is equal to 670?
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Aashu Bhujel

Lvl 1
āˆ™ 1y ago
N^2+2n+3
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Sachin Khanal

Lvl 1
āˆ™ 11mo ago
tn=[n+1]Ā²+2
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Mozon omar

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āˆ™ 2y ago

it's n^2+2n+3

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Aashu Bhujel

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āˆ™ 1y ago

N^2+2n+3

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Anonymous

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āˆ™ 4y ago

n2 +n2

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Q: The nth term to 6 11 18 27 38?
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What is the nth term for 6 11 18 27 38?

The nth term of the sequence is (n + 1)2 + 2.


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The given sequence is an arithmetic sequence with a common difference that increases by 1 with each term. To find the nth term of an arithmetic sequence, you can use the formula: nth term = a + (n-1)d, where a is the first term, n is the term number, and d is the common difference. In this case, the first term (a) is 3 and the common difference (d) is increasing by 1, so the nth term would be 3 + (n-1)(n-1) = n^2 + 2.


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