ans=102 HOW? 6,11,13,27,38,.... 6(+5),11(+7),13(+9),27(+11),38(+13),51(+15),66(+17),83(+19),102adding 5 to 6 gives 11 adding 7(two greater than previous one) gives 13...and so on... to find the nth term N squared +2
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To find the pattern in the sequence 6, 11, 18, 27, 38, we need to calculate the differences between consecutive terms. The differences are 5, 7, 9, 11, which are increasing by 2 each time. This suggests that the pattern is based on quadratic growth. By examining the second differences, which are constant at 2, we can infer that the nth term can be found using a quadratic equation of the form an^2 + bn + c.
Well, darling, if you want the nth term of 6, 11, 18, 27, and 38, you're looking at a pattern where each number is getting bigger by adding the next odd number (1, 2, 3, 4, etc.). So, the nth term formula would be n^2 + 5. Hope that clears things up for you, sugar!
The nth term of the sequence is (n + 1)2 + 2.
The given sequence is an arithmetic sequence with a common difference that increases by 1 with each term. To find the nth term of an arithmetic sequence, you can use the formula: nth term = a + (n-1)d, where a is the first term, n is the term number, and d is the common difference. In this case, the first term (a) is 3 and the common difference (d) is increasing by 1, so the nth term would be 3 + (n-1)(n-1) = n^2 + 2.
each time the number increases by 8 and the original number was 3.This means that nth term = 3+(n-1)8ie. the fourth term 27 would be 3 + (4-1)x8 = 3+24 = 27
Subtract 2 from the sequence and the answer becomes obvious: 1, 4, 9, 16, 25,...,N2 Now, add the 2 back in: 3, 6, 11, 18, 27,...,(N2+2)
Willies