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ans=102 HOW? 6,11,13,27,38,.... 6(+5),11(+7),13(+9),27(+11),38(+13),51(+15),66(+17),83(+19),102adding 5 to 6 gives 11 adding 7(two greater than previous one) gives 13...and so on... to find the nth term N squared +2

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Wiki User

āˆ™ 15y ago
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Anonymous

Lvl 1
āˆ™ 4y ago
I get what you say.. Umn but..Ā  I mentally solved it..Ā  (n+1)^2+2 ... I really don't know how. But it worked šŸ¤£šŸ¤£
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It's Me Legend

Lvl 1
āˆ™ 2y ago
It is tn=nĀ²+2n+3
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Mozon omar

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āˆ™ 2y ago
which term in the sequence is equal to 670?
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Aashu Bhujel

Lvl 1
āˆ™ 1y ago
N^2+2n+3
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Sachin Khanal

Lvl 1
āˆ™ 1y ago
tn=[n+1]Ā²+2
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ProfBot

āˆ™ 3w ago

To find the pattern in the sequence 6, 11, 18, 27, 38, we need to calculate the differences between consecutive terms. The differences are 5, 7, 9, 11, which are increasing by 2 each time. This suggests that the pattern is based on quadratic growth. By examining the second differences, which are constant at 2, we can infer that the nth term can be found using a quadratic equation of the form an^2 + bn + c.

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BettyBot

āˆ™ 3w ago

Well, darling, if you want the nth term of 6, 11, 18, 27, and 38, you're looking at a pattern where each number is getting bigger by adding the next odd number (1, 2, 3, 4, etc.). So, the nth term formula would be n^2 + 5. Hope that clears things up for you, sugar!

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Mozon omar

Lvl 2
āˆ™ 2y ago

it's n^2+2n+3

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Aashu Bhujel

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āˆ™ 1y ago

N^2+2n+3

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Anonymous

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āˆ™ 4y ago

n2 +n2

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Q: The nth term to 6 11 18 27 38?
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