(n+1)2-1
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The pattern in the given sequence is that each term is the result of adding consecutive odd numbers starting from 1. The nth term can be calculated using the formula: nth term = n^2 + (n-1). Therefore, the nth term for the sequence 3, 8, 15, 24, 35 is n^2 + (n-1), where n represents the position of the term in the sequence.
Oh, what a beautiful sequence of numbers you have there! To find the pattern and the nth term, you can see that each number is increasing by adding consecutive odd numbers starting from 1. So, the nth term can be found using the formula n^2 + 2. Keep exploring and painting with numbers, my friend!
Oh, dude, you're hitting me with some math vibes here. So, the sequence you got going on is like, adding consecutive odd numbers starting from 1. The nth term for this sequence is n^2 + 2. But like, who really needs to know that, am I right?
The answer would be 120... You are increasing by odd numbers 8, 15 (difference is 7) 24 (difference of 9) 35 (difference of 11) 48 (difference of 13) 63 (difference of 15).... etc.... increasing the terms by odd numbers 7 , 9, 11, 13, 15, 17, 19, 21.. I hope this helps
15(1)
35 * * * * * That is the next term. The question, however, is about the nth term. And that is 6*n - 1
It is 6n+5 and so the next term will be 35
If you layout the sequence... 3, 8, 15, 24, 35... ok so you find the difference between these 3 to 8= +5 8 to 15= +7 15 yo 24= +9 24 to 35= +11 so now you find something called the second difference which is +2 +2 +2 +2 +2. Then you need to divide the second difference by 2 which is just n^2 as it is a quadratic sequence you are finding. now you do the nth term which is just 1 2 3 4 5 etc. and you do your n squared sequence which is 1 4 9 16 25 etc. and you do your sequence 3 8 15 24 35 you find out that you need from the n squared sequence and your regular sequence which is +2 +4 +6 +8 +10 this is your 2n add 2n to the divided term n squared and you have your answer, Answer= n squared +2n ------> (n^2)+2n